C语言小项目——井字棋游戏（升级版）
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🌟 前言
Wassup guys😎
今天是我们的C语言小项目「井字棋升级版」
Let’s get it！
文章目录
游戏说明
井字棋，又名三子棋，英文名叫Tic-Tac-Toe；
是一种在3x3格子上进行的连珠游戏，和五子棋类似，格线排成井字故得名。
游戏需要的工具仅为纸和笔，然后由分别代表O和X的两个游戏者轮流在格子里留下标记（一般来说先手者为X），任意三个标记形成一条直线，则为获胜。
其游戏过程就像下面这样👇
游戏效果展示
游戏运行结果如下👇
游戏代码
我在函数这一篇总结中，讲过函数的声明和定义，所有这里我用三个文件来实现这个三子棋游戏
友友们可以将以下代码复制到自己的编译器当中运行：
◾ game.h
游戏函数的声明
#pragma once
//游戏函数的声明
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
//棋盘的行数
#define ROW 3
//棋盘的列数
#define COL 3
//初始化棋盘
void InitBoard(char board[ROW][COL], int row, int col);
//打印棋盘
void DisplayBoard(char board[ROW][COL], int row, int col);
//玩家下棋
void PlayerMove(char board[ROW][COL], int row, int col);
//电脑下棋
void ComputerMove(char board[ROW][COL], int row, int col);
//电脑检查自己是否会赢
int CheckComputer(char board[ROW][COL], int row, int col);
//电脑检查玩家是否会赢
int CheckPlayer(char board[ROW][COL], int row, int col, int k);
//判断输赢函数
char Is_Win(char board[ROW][COL], int row, int col);
/*
1.玩家赢 ---> 返回'*'
2.电脑赢 ---> 返回'#'
3. 平局 ---> 返回'P'
4. 继续 ---> 返回'C'
*/
◾ game.c
游戏函数的实现
#define _CRT_SECURE_NO_WARNINGS 1
//游戏函数的实现
#include "game.h"
void InitBoard(char board[ROW][COL], int row, int col)
int i = 0;
for (i = 0; i < row; i++)
int j = 0;
for (j = 0; j < col; j++)
board[i][j] = ' ';
void DisplayBoard(char board[ROW][COL], int row, int col)
int i = 0;
int j = 0;
//row = 3行
//col = 3列
for (i = 0; i < row; i++)
if (i == 0)
printf("┌----┬----┬----┐\\n");
if ((i == 1) || (i == 2))
printf("├----┼----┼----┤\\n");
for (int j = 0; j < col; j++)
printf("│ %c ", board[i][j]);
printf("│\\n");
printf("└----┴----┴----┘\\n");
void PlayerMove(char board[ROW][COL], int row, int col)
int x = 0;
int y = 0;
while (1)
printf("玩家下棋,请输入坐标:> ");
scanf("%d %d", &x, &y);
printf("你下棋的位置↓\\n");
if ((x >= 1 && x <= row) && (y >= 1 && y <= col))
if (board[x-1][y-1] == ' ')
board[x-1][y-1] = 'x';
break;
else
printf("该坐标被占用,请重新输入\\n");
else
printf("坐标非法,超出范围\\n");
void ComputerMove(char board[ROW][COL], int row, int col)
int x = 0;
int y = 0;
//z是判断变量
int z = 0;
z = CheckComputer(board, row, col);
printf("电脑下棋的位置↓\\n");
while (0 == z)
x = rand() % row;
y = rand() % col;
if (board[x][y] == ' ')
board[x][y] = 'o';
break;
//电脑检查自己能不能赢
int CheckComputer(char board[ROW][COL], int row, int col)
int i = 0;
int j = 0;
//k用于返回值
int k = 0;
while (0 == k)
//电脑判断自己在三行上是否会赢
for (i = 0; i < row; i++)
//如果第一个格子和第二个格子都是电脑的棋子，并且第三个格子是空的
//那么电脑直接落子
if (board[i][0] == board[i][1] && (board[i][0] == 'o' || board[i][1] == 'o') && board[i][2] == ' ')
board[i][2] = 'o';
k = 1;
break;
if (board[i][0] == board[i][2] && (board[i][0] == 'o' || board[i][2] == 'o') && board[i][1] == ' ')
board[i][1] = 'o';
k = 1;
break;
if (board[i][1] == board[i][2] && (board[i][1] == 'o' || board[i][2] == 'o') && board[i][0] == ' ')
board[i][0] = 'o';
k = 1;
break;
if (k != 0)
break;
//电脑判断自己在三列上是否会赢
for (j = 0; j < col; j++)
if (board[0][j] == board[1][j] && (board[0][j] == 'o' || board[1][j] == 'o') && board[2][j] == ' ')
board[2][j] = 'o';
k = 1;
break;
if (board[0][j] == board[2][j] && (board[0][j] == 'o' || board[2][j] == 'o') && board[1][j] == ' ')
board[1][j] = 'o';
k = 1;
break;
if (board[1][j] == board[2][j] && (board[1][j] == 'o' || board[2][j] == 'o') && board[0][j] == ' ')
board[0][j] = 'o';
k = 1;
break;
if (k != 0)
break;
//使用while循环判断对角线是否会赢
while (0 == k)
//左边对角线
if (board[0][0] == board[1][1] && (board[0][0] == 'o' || board[1][1] == 'o') && board[2][2] == ' ')
board[2][2] = 'o';
k = 1;
break;
if (board[0][0] == board[2][2] && (board[0][0] == 'o' || board[2][2] == 'o') && board[1][1] == ' ')
board[1][1] = 'o';
k = 1;
break;
if (board[1][1] == board[2][2] && (board[1][1] == 'o' || board[2][2] == 'o') && board[0][0] == ' ')
board[0][0] = 'o';
k = 1;
break;
//右边对角线
if (board[0][2] == board[1][1] && (board[0][2] == 'o' || board[1][1] == 'o') && board[2][0] == ' ')
board[2][0] = 'o';
k = 1;
break;
if (board[0][2] == board[2][0] && (board[0][2] == 'o' || board[2][0] == 'o') && board[1][1] == ' ')
board[1][1] = 'o';
k = 1;
break;
if (board[1][1] == board[2][0] && (board[1][1] == 'o' || board[2][0] == 'o') && board[0][2] == ' ')
board[0][2] = 'o';
k = 1;
break;
break;
k = CheckPlayer(board, row, col, k);
return k;
//检查玩家是否会赢
int CheckPlayer(char board[ROW][COL], int row, int col, int k)
int i = 0;
int j = 0;
while (0 == k)
//判断玩家在三行上是否会赢
for (i = 0; i < row; i++)
if (board[i][0] == board[i][1] && (board[i][0] == 'x' || board[i][1] == 'x') && board[i][2] == ' ')
board[i][2] = 'o';
k = 1;
break;
if (board[i][0] == board[i][2] && (board[i][0] == 'x' || board[i][2] == 'x') && board[i][1] == ' ')
board[i][1] = 'o';
k = 1;
break;
if (board[i][2] == board[i][1] && (board[i][2] == 'x' || board[i][1] == 'x') && board[i][0C语言实现简单的三子棋