java访问asmx接口

Posted 2023-02-15 女装大佬大老李

网上找了很多例子，很多没法用，只有这个成功了记录一下,原链接忘了，大哥不好意思

        <dependency>
            <groupId>commons-httpclient</groupId>
            <artifactId>commons-httpclient</artifactId>
            <version>3.1</version>
        </dependency>

工具类

import org.apache.commons.httpclient.HttpClient;
import org.apache.commons.httpclient.SimpleHttpConnectionManager;
import org.apache.commons.httpclient.methods.PostMethod;

import java.io.IOException;
import java.util.Map;

public class SoapUtil 


    public static String callSoap(String url,String method, Map<String, String> paramMap) throws IOException 
        // 输入服务网址
        HttpClient client = new HttpClient();
        PostMethod post = new PostMethod(url+"/"+method);
        // 设置参数
        if (paramMap != null) 
            for (Map.Entry<String, String> item : paramMap.entrySet()) 
                String key = item.getKey();
                String value = item.getValue();
                System.out.println(key + ":" + value);
                post.setParameter(key, value);
            
        
        // client.setTimeout(newTimeoutInMilliseconds);

        // 执行,返回一个结果码
        int code = client.executeMethod(post);

        System.out.println("结果码：" + code);
        // 获取xml结果
        String result = post.getResponseBodyAsString();
        System.out.println("结果：" + result);
        // 释放连接
        post.releaseConnection();
        // 关闭连接
        ((SimpleHttpConnectionManager) client.getHttpConnectionManager()).shutdown();
        return result;
    

调用

public static void main(String[] args) throws Exception 
       
    Map<String, String> paramMap = new HashMap<>();
    paramMap.put("id", "10086");
    paramMap.put("name", "老李");

    SoapUtil.callSoap("http://120.79.xxx.xxx:1234/aaaa.asmx", "调用的方法", paramMap);