Oracle 查看最近 60s 资源消耗

Posted 2021-09-03 特立独行

指定时间范围为：ASH.SAMPLE_TIME >= SYSDATE - 60 / 24 / 60 / 60),格式原因，调整为/

COL WAIT FOR 999;
COL TOTAL FOR 999;
COL IO FOR 999;
COL CPU FOR 999;
col SCHEMANAME for a16;
COL SID FOR 9999
COL MACHINE FOR A18;
COL OSUSER FOR A15;
COL PROGRAM FOR A30;
COL EVENT FOR A32;
SELECT S.SID,
       ASH.SQL_ID,
       Q.SQL_TEXT,
       S.SCHEMANAME,
       S.EVENT,
       ASH.PROGRAM,
       SUBSTR(ASH.MACHINE,
              INSTR(ASH.MACHINE, \'\' || CHR(92) || \'\', -1, 1) + 1) MACHINE,
       SUBSTR(S.OSUSER, INSTR(S.OSUSER, \'\' || CHR(92) || \'\', -1, 1) + 1) OSUSER,
       SUM(DECODE(ASH.SESSION_STATE, \'ON CPU\', 1, 0)) "CPU",
       SUM(DECODE(ASH.SESSION_STATE, \'WAITING\', 1, 0)) -
       SUM(DECODE(ASH.SESSION_STATE,
                  \'WAITING\',
                  DECODE(ASH.WAIT_CLASS, \'USER I/O\', 1, 0),
                  0)) "WAIT",
       SUM(DECODE(ASH.SESSION_STATE,
                  \'WAITING\',
                  DECODE(ASH.WAIT_CLASS, \'USER I/O\', 1, 0),
                  0)) "IO",
       SUM(DECODE(ASH.SESSION_STATE, \'ON CPU\', 1, 1)) "TOTAL"
  FROM V$ACTIVE_SESSION_HISTORY ASH
  LEFT JOIN V$SESSION S
    ON ASH.SESSION_ID = S.SID
  LEFT JOIN V$SQL Q
    ON S.SQL_ID = Q.SQL_ID
   AND S.SQL_ADDRESS = Q.ADDRESS
   AND S.SQL_HASH_VALUE = Q.HASH_VALUE
 WHERE ASH.SAMPLE_TIME >= SYSDATE - 60 / (24 * 60 * 60)
 GROUP BY S.SID,
          S.SCHEMANAME,
          ASH.SQL_ID,
          Q.SQL_TEXT,
          S.EVENT,
          ASH.PROGRAM,
          SUBSTR(ASH.MACHINE,
                 INSTR(ASH.MACHINE, \'\' || CHR(92) || \'\', -1, 1) + 1),
          SUBSTR(S.OSUSER, INSTR(S.OSUSER, \'\' || CHR(92) || \'\', -1, 1) + 1)
HAVING SUM(DECODE(ASH.SESSION_STATE, \'ON CPU\', 1, 1)) > = 2
 ORDER BY SUM(DECODE(ASH.SESSION_STATE, \'ON CPU\', 1, 1)) DESC;