golang 编写一个程序，打印从1到N的数字。但是对于三个打印的“Fizz”而不是数字，以及ff的倍数的倍数

Posted 2021-05-24

package main

import "fmt"

func main() {
  n := 15
  for i:=1; i<=n; i++ {
    if (i%3 == 0) && (i%5 == 0) {
      fmt.Println("FizzBuzz")
    } else if i%3 == 0 {
      fmt.Println("Fizz")
    } else if i%5 == 0 {
      fmt.Println("Buzz")
    } else {
      fmt.Println(i)
    }
  }
}

java 编写一个从用户读取10个数字的java程序，并在列表中打印第一个奇数。

/*
 * To change this license header, choose License Headers in Project Properties.
 * To change this template file, choose Tools | Templates
 * and open the template in the editor.
 */
package BASICJAVA;

import java.util.Scanner;

/**
 *
 * @author ABIR
 */
public class Array_If_Break_Exit {
    public static void main(String[]args){
        Scanner abir =new Scanner(System.in);
        int[] number=new int[10];
        for (int i = 0; i < number.length; i++) {
            System.out.println("Enter your "+(i+1)+" number");
            number[i]=abir.nextInt();
        }
        for (int i = 0; i < number.length; i++) {
            if (number[i]%2!=0) {
                System.out.println("your first odd number is "+ number[i]);
                break;
            }
        }
    }
}