ActionScript 3 通过ActionScript 3（和as3corelib）获取美味的JSON提要

Posted 2021-05-23

import com.adobe.serialization.json.JSON;

var loader:URLLoader = new URLLoader();
var request:URLRequest = new URLRequest();

request.url = "http://feeds.delicious.com/v2/json";
loader.load(request);
loader.addEventListener(Event.COMPLETE, decodeJSON);

function decodeJSON(event:Event):void {
	var loader:URLLoader = URLLoader(event.target) ;
	var Bookmarks:Array = JSON.decode(loader.data) ;
	
	for (var key:Object in Bookmarks) {
		trace(Bookmarks[key].u);
		trace(Bookmarks[key].d);
		trace(Bookmarks[key].t);
	}
}