ruby 字谜

Posted 2021-05-16

# using reduce
def anagram? a, b
  counts = ->(word) { word.chars.reduce(Hash.new 0) {|h, c| h[c] +=1 unless c =~ /\s/; h} }
  counts[a] == counts[b]
end

# using each_with_object
def anagram? a, b
  counts = ->(word) { word.each_char.with_object(Hash.new 0) { |c, h| h[c] += 1 unless c =~ /\s/} }
  counts[a] == counts[b]
end