PHP 将数据库转储到HTML表
Posted
tags:
篇首语：本文由小常识网(cha138.com)小编为大家整理，主要介绍了PHP 将数据库转储到HTML表相关的知识，希望对你有一定的参考价值。
<?php
$dbname = "test";
$loginname = "user";
$loginpass = "password";
$dbhost = "localhost";
echo('<html><body bgcolor="#FFFFFF">');
echo('<font face="arial" size="+4"><center>');
echo("Database $dbname");
$id_link = @mysql_connect($dbhost, $loginname, $loginpass);
$tables = mysql_list_tables($dbname, $id_link);
$num_tables = mysql_num_rows($tables);
// store table names in an array
$arr_tablenames[] = '';
// store number of fields per table(index 0,1,2..) in an array
$arr_num_fields[] = '';
for ($i=0; $i < $num_tables; $i++) {
$arr_tablenames[$i] = mysql_tablename($tables, $i);
$arr_num_fields[$i] = mysql_num_fields(mysql_db_query($dbname, "select * from $arr_tablenames[$i]", $id_link));
}
// store field names in a multidimensional array:
// [i] == table number, [ii] == field number for that table
for ($i=0; $i < $num_tables; $i++) {
for ($ii=0; $ii < $arr_num_fields[$i]; $ii++) {
$result = mysql_db_query($dbname, "select * from $arr_tablenames[$i]", $id_link);
$hash_field_names[$i][$ii] = mysql_field_name($result, $ii);
}
}
for ($i=0; $i < $num_tables; $i++) {
echo("<center><h2>Table $arr_tablenames[$i] </h2></center>");
echo('<table align="center" border="1"><tr>');
$result = mysql_db_query($dbname, "select * from $arr_tablenames[$i]", $id_link);
for ($ii=0; $ii < $arr_num_fields[$i]; $ii++) {
echo("<th>");
echo $hash_field_names[$i][$ii];
echo("</th>");
}
echo("</tr><tr>");
$number_of_rows = @mysql_num_rows($result);
for ($iii = 0; $iii < $number_of_rows; $iii++) {
$record = @mysql_fetch_row($result);
for ($ii=0; $ii < $arr_num_fields[$i]; $ii++) {
echo("<td>");
echo $record[$ii];
echo("</td>");
}
echo("</tr>");
}
echo("</table>");
}
echo('</body></html>');
?>以上是关于PHP 将数据库转储到HTML表的主要内容，如果未能解决你的问题，请参考以下文章