<?php
/*
Copyright (c) 2008, reusablecode.blogspot.com; some rights reserved.
Thanks to Jim Mayes for showing me a more elegant solution.
This work is licensed under the Creative Commons Attribution License. To view
a copy of this license, visit http://creativecommons.org/licenses/by/3.0/ or
send a letter to Creative Commons, 559 Nathan Abbott Way, Stanford, California
94305, USA.
*/
// Check if a year is a leap year.
function isLeapYear($someYear)
{
return date("L", strtotime($someYear . "-01-01"));
}
?>