PHP 某一天的天数

Posted 2021-05-14

function daysinyear($year)
	{
	$endyear = mktime(24, 0, 0, 12, 31, $year);
	$beginyear = mktime(0, 0, 0, 1, 1, $year);
	$diff = $endyear - $beginyear;
	$days = $diff / (60*60*24);
	return $days;
	}