c_cpp 给定二叉树和总和，确定树是否具有根到叶路径，以便沿路径添加所有值等于gi

Posted 2021-05-14

bool hasPathSum(TreeNode *root, int sum) {
    if(!root) return false;
    if(sum == root->val && root->left == NULL && root->right == NULL) return true;
    return hasPathSum(root->left, sum - root->val) || hasPathSum(root->right, sum - root->val);
}