c_cpp 在静态内存地址上使用memcpy

Posted 2021-05-14

#include "stdio.h"
#include "stdlib.h"
#include "string.h"

int main(void) {
  void* buf = malloc(40);
  int f = 7;
  memcpy(buf, &f, sizeof(int));
  int* foo = buf;
  printf(" first is : %d\n", foo[0]);
  return 0;
}