c_cpp 用位运算实现四则运算之加减乘除的.c

Posted 2021-05-14

#include<iostream>
#include<cstdlib>
using namespace std;

//递归版本的加法实现
int Add(int a, int b)
{
    return b ? Add(a^b, (a&b)<<1) : a;
    /*
    if(b)
        return plus_rec(a^b, (a&b)<<1);
    else
        return a;
        */
}

//该为迭代版本
int Add_iter(int a, int b)
{
    int ans;
    while(b)
    {
        ans = a^b;
        b = (a&b)<<1;
        a = ans;
    }
    return ans;
}

//求a的相反数：将各位取反加一
int negative(int a)     //get -a
{
    return Add(~a, 1);
}

int Minus(int a, int b)
{
    return Add(a, negative(b));
}

//正数乘法
int Multi(int a, int b)
{
    int ans = 0;
    while(b)
    {
        if(b&1)
            ans = Add(ans, a);
        a = a << 1;
        b = b >> 1;
    }
    return ans;
}

//正数除法
int Divide(int a, int b)
{
    int coun = 0;
    while(a >= b)
    {
        a = Minus(a, b);
        coun = Add(coun, 1);
    }
    return coun;
}

//判断是否是负数，0，正数
int isneg(int a)
{
    return a & 0x8000;
}
int iszero(int a)
{
    return !(a & 0xFFFF);
}
int ispos(int a)
{
    return (a&0xFFFF) && !(a&0x8000);
}

//处理负数的乘法和除法
int My_Multi(int a, int b)
{
    if(iszero(a) || iszero(b))
        return 0;
    if(isneg(a))
    {
        if(isneg(b))
            return Multi(negative(a), negative(b));
        else
            return negative(Multi(negative(a), b));
    }else if(isneg(b))
        return negative(Multi(a, negative(b)));
    else
        return Multi(a, b);
}

int My_Divide(int a, int b)
{
    if(iszero(b))
    {
        cout << "Error!" << endl;
        exit(1);
    }
    if(iszero(a))
        return 0;
    if(isneg(a))
    {
        if(isneg(b))
            return Divide(negative(a), negative(b));
        else
            return negative(Divide(negative(a), b));
    }else if(isneg(b))
        return negative(Divide(a, negative(b)));
    else
        return Divide(a, b);

}

int main(int argc, char **argv)
{
    int a = 5;
    int aa = -5;
    int b = 3;
    int bb = -3;
    int c = 15;
    cout << Add(a, b) << endl;
    cout << Add(a, bb) << endl;
    cout << Minus(a, b) << endl;
    cout << Minus(b, a) << endl;
    cout << Multi(a, b) << endl;
    cout << My_Multi(aa, b) << endl;
    cout << Divide(c, a) << endl;

    return 0;
}