c_cpp 设有一半径为[R的圆及其外切四边形。向该正方形随机地投掷Ñ个点。设落入圆内的点数为ķ。由于所投入的点在正方形上均匀分布，因而所投入的点落入圆内的概率为***。所以当ñ足

Posted 2021-05-14

//随机化算法 用随机投点法计算π值
#include "stdafx.h"
#include "RandomNumber.h"
#include <iostream>
using namespace std;
 
double Darts(int n);
 
int main()
{
	int n1 = 100,n2 = 1000,n3 = 1000,n4 = 10000,n5 = 10000000;
	cout<<"n1="<<n1<<",π1="<<Darts(n1)<<endl;
	cout<<"n2="<<n2<<",π2="<<Darts(n2)<<endl;
	cout<<"n3="<<n3<<",π3="<<Darts(n3)<<endl;
	cout<<"n4="<<n4<<",π4="<<Darts(n4)<<endl;
	cout<<"n5="<<n5<<",π5="<<Darts(n5)<<endl;
	return 0;
}
 
//用随机投点法计算π值
double Darts(int n)
{
	static RandomNumber dart;
	int k = 0;
 
	for(int i=1; i<=n; i++)
	{
		double x = dart.fRandom();
		double y = dart.fRandom();
		if((x*x + y*y)<=1)
		{
			k++;
		}
	}
 
	return 4*k/double(n);
}