c_cpp 查找=重复xor具有相同的数字不会更改输出字符。

Posted 2021-05-14

int main(void) {
    unsigned char a = 53;
    unsigned char b = 101;
    unsigned char c = 81;
    unsigned char d = 7;
    for(int i = 0; i < 30; i++) {
        a ^= b;
        a ^= c;
        a ^= d;
        printf("a is now %u\n", a);
        /*
         a is now 6
         a is now 53
         a is now 6
         a is now 53
         a is now 6
         a is now 53
         a is now 6
         a is now 53
         a is now 6
         a is now 53
         a is now 6
         a is now 53
         a is now 6
         a is now 53
         a is now 6
         a is now 53
         a is now 6
         a is now 53
         a is now 6
         a is now 53
         a is now 6
         a is now 53
         a is now 6
         a is now 53
         a is now 6
         a is now 53
         a is now 6
         a is now 53
         a is now 6
         a is now 53*/
    }
    return 0;
}