sql ПодсчетколичествассылоквкомментарияхНПД

Posted 2021-05-14

USE [Content_NPD_COMM]


CREATE FUNCTION dbo.FindPatternLocation
(
    @string NVARCHAR(MAX),
    @term   NVARCHAR(255)
)
RETURNS TABLE
AS
    RETURN 
    (
      SELECT pos = Number - LEN(@term) 
      FROM (SELECT Number, Item = LTRIM(RTRIM(SUBSTRING(@string, Number, 
      CHARINDEX(@term, @string + @term, Number) - Number)))
      FROM (SELECT ROW_NUMBER() OVER (ORDER BY [object_id])
      FROM sys.all_objects) AS n(Number)
      WHERE Number > 1 AND Number <= CONVERT(INT, LEN(@string))
      AND SUBSTRING(@term + @string, Number, LEN(@term)) = @term
    ) AS y);



DECLARE @ModuleID tinyint = 99
DECLARE @ID int = 420282034

DECLARE @MinBID bigint, @MaxBID bigint

SELECT 
	@MinBID = MIN([BacklinkID]), 
	@MaxBID = MAX([BacklinkID])
FROM [Content_NPD_COMM].[dbo].[BacklinkPhrase]
WHERE ModuleID = @ModuleID AND ID = @ID


SELECT COUNT(*)
FROM [dbo].[BacklinkComment]
CROSS APPLY dbo.FindPatternLocation([Comment], 'sp://num=')
WHERE BacklinkID BETWEEN @MinBID AND @MaxBID 


SELECT COUNT(*)
FROM [dbo].[DocIntLnk]
WHERE ModuleFrom = @ModuleID AND IDFrom = @ID