sql [sql]查找多次输入的电子邮件帐户及其计数。

Posted 2021-05-14

SELECT
[TotalCount],
[ExcessCount],
([TotalCount] - [ExcessCount]) [DistinctsCount]
FROM
(
  SELECT SUM([TotalCount]) AS [TotalCount]
  FROM 
  (
    SELECT COUNT(*) AS [TotalCount]
    FROM [Contacts]
    WHERE [Email] IS NOT NULL
    GROUP BY [Email]
    HAVING COUNT(*) > 1
  ) tt1
) t1,
(
  SELECT
  SUM([ExcessCount]) AS [ExcessCount]
  FROM 
  (
    SELECT COUNT(*) - 1 AS [ExcessCount]
    FROM [Contacts]
    WHERE [Email] IS NOT NULL
    GROUP BY [Email]
    HAVING COUNT(*) > 1
  ) tt2
) t2