sql 在SQL中拼出数字值
Posted
tags:
篇首语：本文由小常识网(cha138.com)小编为大家整理，主要介绍了sql 在SQL中拼出数字值相关的知识，希望对你有一定的参考价值。
SET NOCOUNT ON
-- =============================================
-- Author: Copyright 2009 Anthony Zackin
-- Create date: 01-22-09
-- Description: Converts an integer into words, viz.,
-- master.dbo.fnSpellInteger(10129) ==> "Ten Thousand One Hundred Twenty-Nine"
-- =============================================
USE MASTER
IF OBJECT_ID( 'dbo.fnSpellInteger' ) IS NOT NULL DROP FUNCTION fnSpellInteger
GO
CREATE FUNCTION dbo.fnSpellInteger ( @ NUMBER INT )
RETURNS VARCHAR(100)
AS
BEGIN
-- For debugging outside of the UDF: DECLARE @debug bit SET @debug = 0
DECLARE @result VARCHAR(100), @word VARCHAR(100), @ GROUP VARCHAR(100)
DECLARE @i INT , @j INT , @m INT , @digit VARCHAR(2), @cn VARCHAR(20)
IF @ NUMBER = 0 RETURN 'Zero'
SELECT @result = '' , @word = '' , @ GROUP = ''
SET @cn = @ NUMBER
SET @cn = REPLACE(@cn, ',' , '' )
SET @m = LEN(@cn) % 3
IF @m > 0 SET @cn = REPLICATE( '0' ,3 - @m) + @cn -- Left pad with zeroes to a multiple of 3
SET @i = 1
SET @j = LEN(@cn) - @i + 1
SET @m = @i % 3
WHILE @i <= LEN(@cn)
BEGIN
-- @i is 1 origin index into numeric string while @m = @i modulo 3
-- If the middle digit of each group of 3 is a '1' then this is a 'Ten' or a '...teen'
IF @m = 2 AND SUBSTRING (@cn,@i,1) = '1'
BEGIN
SET @digit = SUBSTRING (@cn,@i,2)
-- Skip rightmost digit of 3 if processing teens
SET @i = @i + 1
END
ELSE
SET @digit = SUBSTRING (@cn,@i,1)
SET @word =
CASE
WHEN @m = 0 THEN -- Rightmost digit of group of 3
CASE @digit
WHEN '0' THEN ''
WHEN '1' THEN 'One'
WHEN '2' THEN 'Two'
WHEN '3' THEN 'Three'
WHEN '4' THEN 'Four'
WHEN '5' THEN 'Five'
WHEN '6' THEN 'Six'
WHEN '7' THEN 'Seven'
WHEN '8' THEN 'Eight'
WHEN '9' THEN 'Nine'
END +
CASE
WHEN (@ GROUP <> '' OR @digit <> '0' ) AND (@j + 2) / 3 = 2 THEN ' Thousand'
WHEN (@ GROUP <> '' OR @digit <> '0' ) AND (@j + 2) / 3 = 3 THEN ' Million'
WHEN (@ GROUP <> '' OR @digit <> '0' ) AND (@j + 2) / 3 = 4 THEN ' Billion'
ELSE ''
END
WHEN LEN(@digit) = 2 THEN -- Special case when middle digit is a '1'
CASE @digit
WHEN '10' THEN 'Ten'
WHEN '11' THEN 'Eleven'
WHEN '12' THEN 'Twelve'
WHEN '13' THEN 'Thirteen'
WHEN '14' THEN 'Fourteen'
WHEN '15' THEN 'Fifteen'
WHEN '16' THEN 'Sixteen'
WHEN '17' THEN 'Seventeen'
WHEN '18' THEN 'Eighteen'
WHEN '19' THEN 'Nineteen'
END +
CASE
WHEN (@ GROUP <> '' OR @digit <> '00' ) AND (@j + 2) / 3 = 2 THEN ' Thousand'
WHEN (@ GROUP <> '' OR @digit <> '00' ) AND (@j + 2) / 3 = 3 THEN ' Million'
WHEN (@ GROUP <> '' OR @digit <> '00' ) AND (@j + 2) / 3 = 4 THEN ' Billion'
ELSE ''
END
WHEN @m = 2 THEN -- Middle digit of group of 3
CASE @digit
WHEN '2' THEN 'Twenty'
WHEN '3' THEN 'Thirty'
WHEN '4' THEN 'Forty'
WHEN '5' THEN 'Fifty'
WHEN '6' THEN 'Sixty'
WHEN '7' THEN 'Seventy'
WHEN '8' THEN 'Eighty'
WHEN '9' THEN 'Ninety'
ELSE ''
END
WHEN @m = 1 THEN -- Leftmost digit of group of 3
CASE @digit
WHEN '0' THEN ''
WHEN '1' THEN 'One'
WHEN '2' THEN 'Two'
WHEN '3' THEN 'Three'
WHEN '4' THEN 'Four'
WHEN '5' THEN 'Five'
WHEN '6' THEN 'Six'
WHEN '7' THEN 'Seven'
WHEN '8' THEN 'Eight'
WHEN '9' THEN 'Nine'
END +
CASE WHEN @digit <> '0' THEN ' Hundred' ELSE '' END
END
SET @ GROUP = @ GROUP + RTRIM(@word) -- Group value
IF @word <> ''
BEGIN
DECLARE @prefix VARCHAR(20)
IF CHARINDEX( ' ' ,@word) > 0 SET @prefix = LEFT (@word,CHARINDEX( ' ' ,@word)) ELSE SET @prefix = @word
IF RIGHT (@result,2) = 'ty' AND @prefix IN ( 'One' , 'Two' , 'Three' , 'Four' , 'Five' , 'Six' , 'Seven' , 'Eight' , 'Nine' )
SET @result = @result + '-' + LTRIM(@word)
ELSE
SET @result = @result + ' ' + LTRIM(@word)
END
-- The following needs to be outside of a UDF to work:
--IF @debug = 1 SELECT @cn as 'Number', @i as '@i', @j as '@j', @m as '@m', @digit as '@digit', CAST(replace(@group,' ','`') AS CHAR(30)) as '@group', @word as '@word', @result as '@result'
SET @i = @i + 1
SET @j = LEN(@cn) - @i + 1
SET @m = @i % 3
IF @m = 1 SET @ GROUP = '' -- Clear group value when starting a new one
END
IF @result = '' SET @result = '0'
RETURN LTRIM(@Result)
END
GO
SET NOCOUNT ON
-- =============================================
-- Author: Copyright 2009 Anthony Zackin
-- Create date: 01-22-09
-- Description: Converts a string numeric expression into words, viz.,
-- master.dbo.fnSpellNumber('15.99') ==> "Fifteen and Ninety-Nine Hundredths"
-- Notes: Uses fnSpellInteger to convert an integer into words
-- Example: fnSpellNumber can be used to generate pseudo-random test character data
/*
set nocount on
DECLARE @rand INT, @i INT
set @rand = rand(131)*100
SET @i = 0
while @i < 5
BEGIN
set @i = @i + 1
SELECT 'insert(id,number,words) values(' + CAST(@i AS varchar(5)) + ',' +
cast(@rand as varchar(5)) + ',''' + master.dbo.fnspellnumber(@rand) + ''')'
SET @rand = rand()*100
end
*/
-- =============================================
USE MASTER
IF OBJECT_ID( 'master.dbo.fnSpellNumber' ) IS NOT NULL DROP FUNCTION fnSpellNumber
GO
CREATE FUNCTION dbo.fnSpellNumber ( @ NUMBER varchar(20) )
RETURNS VARCHAR(200)
AS
--For debugging: declare @number varchar(20) set @number = '192.1'
BEGIN
-- This is for use outside of a function: DECLARE @debug bit SET @debug = 0
DECLARE @result varchar(200), @word varchar(100)
DECLARE @i INT , @intpart varchar(20), @decpart varchar(20)
SET @word = LTRIM(RTRIM(@ NUMBER ))
-- Check for a bad number, e.g., one with embedded spaces
IF ISNUMERIC(@word) = 0 RETURN '<< NOT A NUMBER >>'
SET @i = CHARINDEX( '.' , @word)
-- Remove trailing zeroes for any decimal portion
IF @i > 0 -- Number contains a decimal point
BEGIN
WHILE RIGHT (@word,1) = '0' SET @word = LEFT (@word,LEN(@word) - 1)
IF @word = '' SET @word = '0'
END
-- Insert a decimal point at the end if none was specified
IF @i = 0 -- No decimal point
BEGIN
SET @word = @ NUMBER + '.'
SET @i = CHARINDEX( '.' , @word)
END
SET @intpart = LEFT (@word,@i - 1) -- Extract the integer part of the number if any
IF LEN(@intpart) > 0
SET @result = master.dbo.fnSpellInteger( CAST (@intpart AS INT ))
ELSE
SET @result = ''
-- Extract the decimal portion of the number
SET @decpart = RIGHT (@word,LEN(@word) - @i) -- @i is position of decimal point
IF LEN(@decpart) > 0
BEGIN
IF @result = 'Zero'
SET @result = ''
ELSE IF @result <> ''
SET @result = @result + ' and '
SET @result = @result + master.dbo.fnSpellInteger(@decpart) +
CASE LEN(@decpart)
WHEN 0 THEN ''
WHEN 1 THEN ' Tenths'
WHEN 2 THEN ' Hundredths'
WHEN 3 THEN ' One-Thousandths'
WHEN 4 THEN ' Ten-Thousandths'
WHEN 5 THEN ' One-Hundred-Thousandths'
WHEN 6 THEN ' One-Millionths'
WHEN 7 THEN ' Ten-Millionths'
WHEN 8 THEN ' One-Hundred-Millionths'
WHEN 9 THEN ' One-Billionths'
END
-- Check for a valid plural
IF @decpart = 1 SET @result = LEFT (@result, LEN(@result) - 1) -- Remove last "s" for just 1
END
-- This is for use outside of a function: if @debug = 1 select @word as '@word', @i as '@i', @intpart as '@intpart', @decpart as '@decpart', @result as '@result'
RETURN @result
END
GO
以上是关于sql 在SQL中拼出数字值的主要内容，如果未能解决你的问题，请参考以下文章