sql [从马歇尔选择最高级别的sherlock xmatches] #xmatch #sherlock #pessto #marshall

Posted 2021-05-13

SELECT
    *
FROM
    (SELECT
        a.catalogue_table_id,
            a.catalogue_table_name,
            a.all_count,
            COALESCE(top_rank_count, 0) AS `top_rank_count`
    FROM
        (SELECT
        COUNT(*) AS all_count,
            catalogue_table_name,
            catalogue_table_id
    FROM
        sherlock_crossmatches
    GROUP BY catalogue_table_name) AS a
    LEFT JOIN (SELECT
        COUNT(*) AS `top_rank_count`,
            catalogue_table_name,
            catalogue_table_id
    FROM
        sherlock_crossmatches
    WHERE
        rank = 1
    GROUP BY catalogue_table_name) AS b ON a.catalogue_table_id = b.catalogue_table_id) AS s;