csharp 获取控制器中的所有动作和描述

Posted 2021-05-12

           
           // 获取controller中的所有action和description
           Assembly asm = Assembly.GetAssembly(typeof(NjModelmgr.MvcApplication));
            var controlleractionlist = asm.GetTypes()
                    .Where(type => typeof(System.Web.Mvc.Controller).IsAssignableFrom(type))
                    .SelectMany(type => type.GetMethods(BindingFlags.Instance | BindingFlags.DeclaredOnly | BindingFlags.Public))
                    .Where(m => !m.GetCustomAttributes(typeof(System.Runtime.CompilerServices.CompilerGeneratedAttribute), true).Any())
                    .Select(x => new
                    {
                        Controller = x.DeclaringType.Name,
                        Action = x.Name,
                        Attributes = String.Join(",", x.GetCustomAttributes().Select(a => a.GetType().Name.Replace("Attribute", ""))),
                        Description = ((DescriptionAttribute)x.GetCustomAttribute(typeof(DescriptionAttribute))) == null ? "" : ((DescriptionAttribute)x.GetCustomAttribute(typeof(DescriptionAttribute))).Description
                    })
                    .OrderBy(x => x.Controller).ThenBy(x => x.Action).ToList();
            var jsonData = JsonConvert.SerializeObject(controlleractionlist);
            return Content(jsonData);