html Примерзапускасообщенийизphp

Posted 2021-05-11

<?php
    if(isset($_POST['foo']) && $_POST['foo'] != "") {
        $query = WRITE_TO_DB_QUERY
        $result = mysqli_query($query);
        if($result) {
            // notice how I'm just writing regular JS to the page
            echo "
                <script type='text/javascript'>
                    $(document).ready(function(e) {
                        notifyUser('success');
                    });
                </script>";
        } else {
            echo "
                <script type='text/javascript'>
                    $(document).ready(function(e) {
                        notifyUser('failure');
                    });
                </script>";
        }
    }
?>
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post">
    <input type="text" name="foo" />
    <input type="submit" value="Submit" />
</form>
<script type="text/javascript">
    function notifyUser(message) {
        if(message == "success") {
            new PNotify({
                title: 'Popup Title',
                text: 'Your form as been submitted'
            });
        } else {
            new PNotify({
                title: 'Popup Title',
                text: 'Whops, you messed up'
            }); 
        }
    }
</script>