html 测试Joshua Canfield投资组合

Posted

tags:

篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了html 测试Joshua Canfield投资组合相关的知识,希望对你有一定的参考价值。

Testing for Joshua Canfield Portfolio
-------------------------------------


A [Pen](http://codepen.io/jcanfield/pen/mWzxPR) by [Joshua Canfield](http://codepen.io/jcanfield) on [CodePen](http://codepen.io/).

[License](http://codepen.io/jcanfield/pen/mWzxPR/license).
@import "neat";
@import "modular-scale";
@import "compass";
@import "breakpoint";
@import "susy";
body { background: #303336; }
<script src="https://platform.linkedin.com/badges/js/profile.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.1.1/jquery.min.js"></script>
/* Auto generated, hash = 90d22umjselkp5q5gm7q9i58o */
(function(c){c.LIRenderAll=function(){function q(a){return Array.prototype.slice.call(a.attributes).filter(function(a){return-1!==a.name.lastIndexOf("data-key-",0)}).map(function(a){return encodeURIComponent(a.name.replace("data-","").toLowerCase())+"\x3d"+encodeURIComponent(a.value)})}function r(a){var c=a.getAttribute("data-size"),b=a.getAttribute("data-locale"),g=a.getAttribute("data-type"),e=a.getAttribute("data-theme"),k=a.getAttribute("data-vanity"),h=a.getAttribute("data-version"),f=a.getAttribute("data-ei"),
l=a.getAttribute("data-entity"),m=a.getAttribute("data-iscreate"),d=Math.round(1E6*Math.random()),f=f?"https://badges.linkedin-ei.com/":"https://badges.linkedin.com/",b=["locale\x3d"+encodeURIComponent(b),"badgetype\x3d"+encodeURIComponent(g),"badgetheme\x3d"+encodeURIComponent(e),"uid\x3d"+encodeURIComponent(d),"version\x3d"+encodeURIComponent(h)];"v2"===h?(f+="view",b.push("badgesize\x3d"+encodeURIComponent(c)),b.push("entity\x3d"+encodeURIComponent(l)),b=b.concat(q(a))):(f+="profile",b.push("maxsize\x3d"+
encodeURIComponent(c)),b.push("trk\x3d"+encodeURIComponent("profile-badge")),b.push("vanityname\x3d"+encodeURIComponent(k)));m&&b.push("fromCreate\x3dtrue");c=f+"?"+b.join("\x26");a.setAttribute("data-uid",d);a=document.createElement("script");a.src=c;n.push(a);document.body.appendChild(a)}function s(){if(m>=d&&0<d||m>=g.length)delete c.LIBadgeCallback,n.map(function(a){document.body.removeChild(a)})}var m=0,d=0,n=[],g=document.getElementsByClassName("LI-profile-badge"),k,h,l,p;k=0;for(h=g.length;k<
h;k++)l=g[k],p=l.getAttribute("data-rendered"),p||(d++,l.setAttribute("data-rendered",!0),r(l));c.LIBadgeCallback=function(a,c){m++;var b,d,e;b=0;for(h=g.length;b<h;b++)d=g[b],e=parseInt(d.getAttribute("data-uid"),10),e===c&&(e=document.createElement("div"),e.innerHTML=a,d.appendChild(e));s()}};"complete"===document.readyState?c.LIRenderAll():c.addEventListener("load",c.LIRenderAll,!1)})(window);
0
<body>

<div class="LI-profile-badge"  data-version="v1" data-size="large" data-locale="en_US" data-type="vertical" data-theme="dark" data-vanity="joshgcanfield"><a class="LI-simple-link" href='https://www.linkedin.com/in/joshgcanfield?trk=profile-badge'>Joshua Canfield</a></div>
  
<script type="text/javascript" src="https://platform.linkedin.com/badges/js/profile.js" async defer></script>
</body>

以上是关于html 测试Joshua Canfield投资组合的主要内容,如果未能解决你的问题,请参考以下文章

String,StringBuilder和StringBuffer整理汇总

单元测试--结队

对具有名称的元组列表进行排序[重复]

Parser Generator Tips翻译(中英对译) by Joshua Xu

谁能解释一下 Joshua Bloch 第 41 条的例子? [复制]

Joshua Bloch 在 Effective Java 中解释的枚举类型