html 将数据参数传递给ajax调用

Posted 2021-05-11

<script>
  
  $.ajax({
    url: "discount.php?e="+<?php echo intval($_POST["id"]);?>+"&c="+code,
      success: function(data){

        if(data.indexOf('%') === -1) {  // if % is not found on discount ticket
          console.log("non percentage discount") ;
          discount = parseInt(data);
          if (discount>0) 
          discount = 0-discount;
          $('#discount_amount').val(discount);
                
        }  
      }
	        
</script>