python 当Exception发生时，使用traceback模块获取更多的stackinfo

Posted 2021-05-09

# coding:UTF-8

import sys
import traceback

def a():
    print("a")
    b()

def b():
    print("b")
    try:
        c()
    except Exception as e:
        print("="*90)
        traceback.print_exc() # 1
        print("="*90)
        sys.stderr.write(traceback.format_exc()) # 2
        sys.stderr.flush()
        print("="*90)
        type, val, tb = sys.exc_info() # 3
        print(type)
        print(val)
        for filename, linenum, funcname, source in traceback.extract_tb(tb):
            print(filename, linenum, funcname, source)


def c():
    print("c")
    raise IndexError("some error")

def main():
    a()

if __name__ == "__main__":
    main()