python 如果它是python中另一个列表的子列表，则返回列表的索引

Posted 2021-05-09

def find_sublist(l1,l2,depth=0):
    """ returns the index of a list in another list 
        by: Cody Kochmann """
    if not len(l1) or not len(l2): return -1
    return depth if l2[:len(l1)] == l1 else find_sublist(l1, l2[1:], depth+1)