python perceptron.py

Posted

tags:

篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了python perceptron.py相关的知识,希望对你有一定的参考价值。

import numpy as np


class Perceptron(object):
    """Perceptron classifier.

    Parameters
    ------------
    eta : float
        Learning rate (between 0.0 and 1.0)
    n_iter : int
        Passes over the training dataset.

    Attributes
    -----------
    w_ : 1d-array
        Weights axfter fitting.
    errors_ : list
        Number of misclassifications (updates) in each epoch.

    """
    def __init__(self, eta=0.01, n_iter=10):
        self.eta = eta
        self.n_iter = n_iter

    def fit(self, X, y):
        """Fit training data.

        Parameters
        ----------
        X : {array-like}, shape = [n_samples, n_features]
            Training vectors, where n_samples is the number of samples and
            n_features is the number of features.
        y : array-like, shape = [n_samples]
            Target values.

        Returns
        -------
        self : object

        """
        self.w_ = np.zeros(1 + X.shape[1])
        self.errors_ = []

        for _ in range(self.n_iter):
            errors = 0
            for xi, target in zip(X, y):
                update = self.eta * (target - self.predict(xi))
                self.w_[1:] += update * xi
                self.w_[0] += update
                errors += int(update != 0.0)
            self.errors_.append(errors)
        return self

    def net_input(self, X):
        """Calculate net input"""
        return np.dot(X, self.w_[1:]) + self.w_[0]

    def predict(self, X):
        """Return class label after unit step"""
        return np.where(self.net_input(X) >= 0.0, 1, -1)

    def score(self, X, Y):
        Y_pred = self.predict(X)
        diff = (Y==Y_pred).sum()
        return float(diff)/float(Y.size)    

if __name__ == "__main__":
    import pandas as pd
    
    df = pd.read_csv('https://archive.ics.uci.edu/ml/'
        'machine-learning-databases/iris/iris.data', header=None)
    
    y = df.iloc[0:100, 4].values
    y = np.where(y == 'Iris-setosa', -1, 1)

    # extract sepal length and petal length
    X = df.iloc[0:100, [0, 2]].values

    ppn = Perceptron(eta=0.1, n_iter=10)
    ppn.fit(X, y)
    print ppn.score(X, y)

以上是关于python perceptron.py的主要内容,如果未能解决你的问题,请参考以下文章

代写python,代写python编程,python代写,python编程代写,留学生python代写

001--python全栈--基础知识--python安装

Python代写,Python作业代写,代写Python,代做Python

Python开发

Python,python,python

Python 介绍