python 从排序的OrderedDict获取键/值。

Posted 2021-05-09

from collections import OrderedDict

d = {'A': 3,
     'B': 2,
     'C': 1}

OrderedDict(sorted(d.items(), key=lambda x: x[0])).values()
# Out[1]: odict_values([3, 2, 1])
OrderedDict(sorted(d.items(), key=lambda x: x[1])).values()
# Out[2]: odict_values([1, 2, 3])
OrderedDict(sorted(d.items(), key=lambda x: x[0])).keys()
# Out[3]: odict_keys(['A', 'B', 'C'])
OrderedDict(sorted(d.items(), key=lambda x: x[1])).keys()
# Out[4]: odict_keys(['C', 'B', 'A'])

# reverse
OrderedDict(sorted(d.items(), key=lambda x: x[0], reverse=True)).values()
# Out[5]: odict_values([1, 2, 3])

# get list
list(OrderedDict(sorted(d.items(), key=lambda x: x[0])).values())
# Out[6]: [3, 2, 1]