python 按自定义lambda函数排序

Posted 2021-05-09

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import datetime

CURRENT_DATE = datetime.date.today()
DAY_DELTA = datetime.timedelta(days=1)

END_DATE = CURRENT_DATE - DAY_DELTA
START_DATE = END_DATE - datetime.timedelta(days=END_DATE.weekday())

SEASON_DATES = [
    ("jan", datetime.date(END_DATE.year, 1, 1)),
    ("apr", datetime.date(END_DATE.year - 1 if END_DATE.month < 4 else END_DATE.year, 4, 1)),
    ("may", datetime.date(END_DATE.year - 1 if END_DATE.month < 5 else END_DATE.year, 5, 1)),
    ("jul", datetime.date(END_DATE.year - 1 if END_DATE.month < 7 else END_DATE.year, 7, 1)),
    ("sep", datetime.date(END_DATE.year - 1 if END_DATE.month < 9 else END_DATE.year, 9, 1)),
    ("oct", datetime.date(END_DATE.year - 1 if END_DATE.month < 10 else END_DATE.year, 10, 1)),
    ("week", START_DATE)
]
SEASON_SEQUENCE = sorted(SEASON_DATES, reverse=True, key=lambda elem: (END_DATE - elem[1]).days)

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