python 使用Python发送和接收电子邮件

Posted 2021-05-09

Use Python to:
- send a plain text email
- send an email with attachment
- receive and filter emails according to some criteria

import smtplib
from email.mime.text import MIMEText

smtp_ssl_host = 'smtp.gmail.com'  # smtp.mail.yahoo.com
smtp_ssl_port = 465
username = 'USERNAME or EMAIL ADDRESS'
password = 'PASSWORD'
sender = '[e-mail]'
targets = ['[e-mail]', '[e-mail]']

msg = MIMEText('Hi, how are you today?')
msg['Subject'] = 'Hello'
msg['From'] = sender
msg['To'] = ', '.join(targets)

server = smtplib.SMTP_SSL(smtp_ssl_host, smtp_ssl_port)
server.login(username, password)
server.sendmail(sender, targets, msg.as_string())
server.quit()

import os
import smtplib
from email.mime.text import MIMEText
from email.mime.image import MIMEImage
from email.mime.multipart import MIMEMultipart

smtp_ssl_host = 'smtp.gmail.com'  # smtp.mail.yahoo.com
smtp_ssl_port = 465
username = 'USERNAME or EMAIL ADDRESS'
password = 'PASSWORD'
sender = '[e-mail]'
targets = ['[e-mail]', '[e-mail]']

msg = MIMEMultipart()
msg['Subject'] = 'I have a picture'
msg['From'] = sender
msg['To'] = ', '.join(targets)

txt = MIMEText('I just bought a new camera.')
msg.attach(txt)

filepath = '/path/to/image/file'
with open(filepath, 'rb') as f:
    img = MIMEImage(f.read())

img.add_header('Content-Disposition',
               'attachment',
               filename=os.path.basename(filepath))
msg.attach(img)

server = smtplib.SMTP_SSL(smtp_ssl_host, smtp_ssl_port)
server.login(username, password)
server.sendmail(sender, targets, msg.as_string())
server.quit()

import time
from itertools import chain
import email
import imaplib

imap_ssl_host = 'imap.gmail.com'  # imap.mail.yahoo.com
imap_ssl_port = 993
username = 'USERNAME or EMAIL ADDRESS'
password = 'PASSWORD'

# Restrict mail search. Be very specific.
# Machine should be very selective to receive messages.
criteria = {
    'FROM':    'PRIVILEGED EMAIL ADDRESS',
    'SUBJECT': 'SPECIAL SUBJECT LINE',
    'BODY':    'SECRET SIGNATURE',
}
uid_max = 0


def search_string(uid_max, criteria):
    c = list(map(lambda t: (t[0], '"'+str(t[1])+'"'), criteria.items())) + [('UID', '%d:*' % (uid_max+1))]
    return '(%s)' % ' '.join(chain(*c))
    # Produce search string in IMAP format:
    #   e.g. (FROM "[e-mail]" SUBJECT "abcde" BODY "123456789" UID 9999:*)


def get_first_text_block(msg):
    type = msg.get_content_maintype()

    if type == 'multipart':
        for part in msg.get_payload():
            if part.get_content_maintype() == 'text':
                return part.get_payload()
    elif type == 'text':
        return msg.get_payload()


server = imaplib.IMAP4_SSL(imap_ssl_host, imap_ssl_port)
server.login(username, password)
server.select('INBOX')

result, data = server.uid('search', None, search_string(uid_max, criteria))

uids = [int(s) for s in data[0].split()]
if uids:
    uid_max = max(uids)
    # Initialize `uid_max`. Any UID less than or equal to `uid_max` will be ignored subsequently.

server.logout()


# Keep checking messages ...
# I don't like using IDLE because Yahoo does not support it.
while 1:
    # Have to login/logout each time because that's the only way to get fresh results.

    server = imaplib.IMAP4_SSL(imap_ssl_host, imap_ssl_port)
    server.login(username, password)
    server.select('INBOX')

    result, data = server.uid('search', None, search_string(uid_max, criteria))

    uids = [int(s) for s in data[0].split()]
    for uid in uids:
        # Have to check again because Gmail sometimes does not obey UID criterion.
        if uid > uid_max:
            result, data = server.uid('fetch', uid, '(RFC822)')  # fetch entire message
            msg = email.message_from_string(data[0][1])
            
            uid_max = uid
        
            text = get_first_text_block(msg)
            print 'New message :::::::::::::::::::::'
            print text

    server.logout()
    time.sleep(1)