java 131.回文分区(#1 DFS).java

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public class Solution {
 	public static List<List<String>> partition(String s) {
		int len = s.length();
		List<List<String>>[] result = new List[len + 1];
		result[0] = new ArrayList<List<String>>();
		result[0].add(new ArrayList<String>());

		boolean[][] pair = new boolean[len][len];
		for (int i = 0; i < s.length(); i++) {
			result[i + 1] = new ArrayList<List<String>>();
			for (int left = 0; left <= i; left++) {
				if (s.charAt(left) == s.charAt(i) && (i-left <= 1 || pair[left + 1][i - 1])) {
					pair[left][i] = true;
					String str = s.substring(left, i + 1);
					for (List<String> r : result[left]) {
						List<String> ri = new ArrayList<String>(r);
						ri.add(str);
						result[i + 1].add(ri);
					}
				}
			}
		}
		return result[len];
	}
}
class Solution {
    
    public List<List<String>> partition(String s) {
        List<List<String>> res = new ArrayList<>();
        if (s == null || s.length() < 1) return res;
        int len = s.length();
        boolean[][] dp = new boolean[len][len];
        for (int i = len - 1; i >= 0; i--) {
            for (int j = i; j < len; j++) {
                if (s.charAt(i) == s.charAt(j) && (j - i < 2 || dp[i + 1][j - 1])) {
                    dp[i][j] = true;
                }
            }
        }
        backtracking(s, 0, dp, new ArrayList<>(), res);
        return res;
    }
    
    public void backtracking(String s, int start, boolean[][] dp, List<String> temp, List<List<String>> res) {
            if (start == s.length()) {
                res.add(new ArrayList<>(temp));
                return;
            }
            for (int i = start; i < s.length(); i++) {
                if (dp[start][i]) {
                    temp.add(s.substring(start, i + 1));
                    backtracking(s, i + 1, dp, temp, res);
                    temp.remove(temp.size() - 1);
                }
            }
        }
}
public class Solution {
    private boolean isPalindrome(StringBuilder sb) {
        if (sb.length() < 2) return true;
        int i = 0;
        int j = sb.length() - 1;
        while (i < j) {
            if (sb.charAt(i) != sb.charAt(j)) return false;
            i++;
            j--;
        }
        return true;
    }
    private void helper(char[] str, int idx, List<String> temp, List<List<String>> res) {
        if (idx == str.length) {
            res.add(new ArrayList<String>(temp));
        }
        StringBuilder sb = new StringBuilder();
        for (int i = idx; i < str.length; i++) {
            sb.append(str[i]);
            if (isPalindrome(sb)) {
                temp.add(sb.toString());
                helper(str, i + 1, temp, res);
                temp.remove(temp.size() - 1);
            }
        }
    }
    public List<List<String>> partition(String s) {
        List<List<String>> res = new ArrayList<>();
        if (s == null || s.length() < 1) return res;
        helper(s.toCharArray(), 0, new ArrayList<String>(), res);
        return res;
    }
}

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Leetcode No.131 分割回文串(DFS)