sh 在一秒钟内重复评估CPU占用最多的CPU（至少保持一个核心忙于100％）并且杀死p

Posted 2021-05-07

#!/bin/bash

declare -a pids

for i in {1..10}
do 
	toptask=$(ps -eo pcpu=,pid= | sed 's/^ *//' | tr -s ' ' '\t' | sort -grk1 | head -1)
	cpu=$(echo $toptask | tr -s ' ' '\t' | cut -f1 | cut -d. -f1)
	pid=$(echo $toptask | tr -s ' ' '\t' | cut -f2)
	if (( cpu > 100 )); then
		pids+=($pid)
	fi
	
	sleep 0.1
done

if [ ! -z ${pids[*]} ]
then
	pid=$(echo ${pids[*]} | tr ' ' '\n' | sort | uniq -c | sed 's/^ *//' | tr -s ' ' '\t' | sort -grk1 | head -n1 | cut -f2)
	kill -9 $pid
	echo "Killed $pid. That was a rogue one!"
else
	echo "No rogue process. Nothing done!"
fi