javascript 检查字符串与indexOf的相似性

Posted 2021-05-04

function mutation(arr) {
  // Turn both inputs lower case, ignoring case completely
  var word = arr[0].toLowerCase();
  var word2 = arr[1].toLowerCase();
  
  for(var i = 0; i < word2.length; i++) {
    // Check word's contents against those of word2, by individual letter. If indexOf returns -1, return false
    if (word.indexOf(word2[i]) != -1 === false) {
      return false;
    }
    // Else return true
  } return true;
}


// Example call
mutation(["hello", "hey"]);