javascript accumulate（）：按顺序执行promises或promise-returns函数数组，并使用给定的累加器减少结果

Posted 2021-05-04

const waterfall = require('promise.waterfall')
const Bluebird = require('bluebird')
const _ = require('lodash')

// an array of 10ms functions with different return values
const functions = [
  () => Bluebird.delay(10, 'a'),
  () => Bluebird.delay(10, 'b'),
  () => Bluebird.delay(10, 'c')
]

/** Executes an array of promises or promise-returning functions serially and reduces thes results with the given accumulator */
function promiseReduce(functionsOrPromises, acculumator, start) {
  return waterfall(functionsOrPromises.map((o, i) => {
    const p = typeof o === 'function' ? o() : o
    return acc => p.then(result => acculumator(i === 0 ? start : acc, result))
  }))
}

/** Executes an array of promises or promise-returning functions serially and returns an array of the results. */
function accumulate(functions) {
  return promiseReduce(functions, _.concat, [])
}

accumulate(functions)
  .then(console.log)
  .catch(console.error)


// can be done more directly, albeit a little more complex
functions.reduce((accPromise, f) =>
  f().then(result =>
    accPromise.then(acc => acc.concat(result))
  ), Promise.resolve([])
)
  .then(console.log)
  .catch(console.error)