javascript 合并Promise.all的结果

Posted 2021-05-04

const a = new Promise(r => r({ a: 'A' }));
const b = new Promise(r => r({ b: 'B' }));
const c = new Promise(r => r({ c: 'C' }));
const result = (async () => {
  const abc = await Promise.all([a, b, c]);
  return abc.reduce((result, obj) => ({...result, ...obj}), {});
})();