javascript ajax请求返回html并将其重新链接到元素而不刷新整个页面

Posted 2021-05-03

function renderView(id) {
    let req = $.ajax({
        url : '/render', // url to post
        type : 'POST', // post request
        data : { "id": id } // payload
    });

    req.done(function (data) {
        // when done, perform the following with the acceprated json (render html)
        // the html will be rendered to an element with id = mainContainder
        $('#mainContainer').html((data));
    });
}