javascript 一个简单的XHR请求

Posted 2021-05-03

function successListener() {  
  var data = JSON.parse(this.responseText);  
  console.log(data);  
}

function failureListener(err) {  
  console.log('Request failed', err);  
}

var request = new XMLHttpRequest();  
request.onload = successListener;  
request.onerror = failureListener;  
request.open('get', './api/some.json', true);  
request.send();