text leetcode练习（832.翻转图像）

Posted 2021-05-02

class Solution:
    def flipAndInvertImage(self, A):
        """
        :type A: List[List[int]]
        :rtype: List[List[int]]
        """
        def invert(value):
            if value==1:
                return 0
            else:
                return 1
            
        for ListIn in A:
            ListCopy = ListIn[:] # cannot use ListCopy = List, otherwise error will appear
            print (ListCopy)
            for i in range(len(A[0])):
                
                ListIn[i] = invert(ListCopy[len(A[0])-i-1])
                
        return A