SpringBoot - MySQL - 列表错误中的未知列字段

Posted 2023-02-26

【中文标题】SpringBoot - MySQL - 列表错误中的未知列字段

【英文标题】：SpringBoot - MySQL - Unknown column field in list error

【发布时间】：2018-07-21 01:34:32

【问题描述】：

以下是我的 Spring boot Rest API 应用程序。

Vendor.Java

package hello;

import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.Id;

@Entity(name="vendor")
public class Vendor 

    @Id
    @Column(name="vendorId")
    private int vendorId;
    @Column(name="vendorName")
    private String vendorName;
    @Column(name="vendorPhone")
    private int vendorPhone;
    @Column(name="vendorBalance")
    private int vendorBalance;
    @Column(name="vendorChequeAmount")
    private int vendorChequeAmount;


    public int getVendorId() 
        return vendorId;
    
    public void setVendorId(int vendorId) 
        this.vendorId = vendorId;
    
    public String getVendorName() 
        return vendorName;
    
    public void setVendorName(String vendorName) 
        this.vendorName = vendorName;
    
    public int getVendorPhone() 
        return vendorPhone;
    
    public void setVendorPhone(int vendorPhone) 
        this.vendorPhone = vendorPhone;
    
    public int getVendorBalance() 
        return vendorBalance;
    
    public void setVendorBalance(int vendorBalance) 
        this.vendorBalance = vendorBalance;
    
    public int getVendorChequeAmount() 
        return vendorChequeAmount;
    
    public void setVendorChequeAmount(int vendorChequeAmount) 
        this.vendorChequeAmount = vendorChequeAmount;
    

VendorRepository.Java

package hello;

import org.springframework.data.repository.CrudRepository;

import hello.Vendor;

// This will be AUTO IMPLEMENTED by Spring into a Bean called userRepository
// CRUD refers Create, Read, Update, Delete

public interface VendorRepository extends CrudRepository<Vendor, Integer> 

MainController.Java

package hello;

import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.GetMapping;
import org.springframework.web.bind.annotation.RequestParam;
import org.springframework.web.bind.annotation.ResponseBody;

import hello.Vendor;
import hello.VendorRepository;

@Controller    // This means that this class is a Controller
@RequestMapping(path="/demo") // This means URL's start with /demo (after Application path)
public class MainController 
    @Autowired // This means to get the bean called userRepository
               // Which is auto-generated by Spring, we will use it to handle the data
    private VendorRepository vendorRepository;

    @GetMapping(path="/all")
    public @ResponseBody Iterable<Vendor> getAllVendors() 
        // This returns a JSON or XML with the users
        return vendorRepository.findAll();
    
    @GetMapping(path="/msg")
    public @ResponseBody String getMsg()
        return "Hi";
    

Application.Java

package hello;

import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.SpringBootApplication;

@SpringBootApplication
public class Application 

    public static void main(String[] args) 
        SpringApplication.run(Application.class, args);
    

当我尝试访问 @http://localhost:8089/demo/all 时出现以下错误

Whitelabel Error Page
This application has no explicit mapping for /error, so you are seeing this as a fallback.

Sat Feb 10 14:59:39 GST 2018
There was an unexpected error (type=Internal Server Error, status=500).
could not extract ResultSet; SQL [n/a]; nested exception is org.hibernate.exception.SQLGrammarException: could not extract ResultSet

请查看错误：-

Application.properties

server.port=8089
spring.jpa.hibernate.ddl-auto=none
spring.jpa.properties.hibernate.show_sql=true
spring.jpa.properties.hibernate.use_sql_comments=true
spring.jpa.properties.hibernate.format_sql=true
spring.jpa.properties.hibernate.type=trace 
spring.jpa.hibernate.naming.strategy=org.hibernate.cfg.EJB3NamingStrategy
spring.datasource.url=jdbc:mysql://localhost:3306/web_customer_tracker
spring.datasource.username=springstudent
spring.datasource.password=springstudent

仍然，我得到了错误：

这是什么错误？如何解决？

【参考方案1】：

从错误信息来看，似乎是在 SQL 查询中生成了错误的列名。我建议在开发时在application.properties 中设置spring.jpa.show-sql=true 以在控制台中查看生成的查询。

该错误很奇怪，因为当您将其名称设置为 vendorId 时，它会抱怨列 vendor_id（werid 数据库列命名策略，顺便说一句）。稍微研究了一下，我遇到了this question，根据它的第一个答案，它似乎是某种列名的错误。如那里所说，尝试将其添加到您的application.preferences：

spring.jpa.hibernate.naming_strategy=org.hibernate.cfg.EJB3NamingStrategy

【讨论】：

您好，请查看我的 application.properties。此外，我无法看到控制台中生成的 SQL 查询。我正在将应用程序作为 Java 应用程序运行。

我作为 Spring boot App 运行，我可以在日志中看到生成的 SQL。是的，这是错误的..Hibernate: /* select generatedAlias0 from vendor as generatedAlias0 */ select vendor0_.vendor_id as vendor_i1_0_, vendor0_.vendor_balance 作为 vendor_b2_0_, vendor0_.vendor_cheque_amount 作为 vendor_c3_0_, vendor0_.vendor_name 作为 vendor_n4_0_, vendor0_.vendor_phone 作为 vendor_p5_0_ from供应商 vendor0_

【参考方案2】：

如果您使用的是 Hibernate v5，请在 application.properties 中使用以下行

spring.jpa.hibernate.naming.physical-strategy=org.hibernate.boot.model.naming.PhysicalNamingStrategyStandardImpl

【参考方案3】：

我刚刚尝试使用小写的列名，它成功了！

@Id
@Column(name="vendorid")
private int vendorId;
@Column(name="vendorname")
private String vendorName;
@Column(name="vendorphone")
private int vendorPhone;
@Column(name="vendorbalance")
private int vendorBalance;
@Column(name="vendorchequeamount")
private int vendorChequeAmount;