如何使用 apache poi 确定合并单元格中的行数?
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【中文标题】如何使用 apache poi 确定合并单元格中的行数?【英文标题】:How to determine number of rows in a merged cell using apache poi? 【发布时间】:2019-01-11 00:55:12 【问题描述】:我正在使用 excel 为我的测试自动化脚本输入数据,当我知道要读取的确切行和列时,我可以从 excel 中读取数据。我面临的挑战是当我在工作表中合并单元格时。例如。 Test data excel sample
这里 ScriptName 和 Iteration 是我的主键,用于标识我的脚本的一组唯一数据。 所以我的问题是:
-
我想获取关于 ScriptName 的所有 ReferenceSetName,以及 Iteration 即登录脚本,Iteration 1:我必须获取 ABC1 Ref set、ABC2 Ref set、ABC3 Ref set李>
我想获取关于 ScriptName、Iteration 和 ReferenceSet 的所有 PackageName,即登录脚本、Iteration 1、ReferenceSet ABC1 Ref 集:我必须获取 ABC1、ABC2、ABC3
目前下面是方法 - getEntireCellValue() 我用来从 excel 中获取数据,我需要帮助来解决上述 2 个问题。任何形式的支持都非常感谢。
public void getExcelRowNum()
boolean found = false;
String scriptCell = null, iterationCell = null;
try
@SuppressWarnings("rawtypes")
Iterator iterator = sheet.rowIterator();
while (iterator.hasNext())
Row row = (Row) iterator.next();
scriptCell = row.getCell(1).toString().trim();
iterationCell = row.getCell(2).toString().trim();
if (row.getCell(2).getCellTypeEnum() == CellType.NUMERIC)
iterationCell = iterationCell.substring(0, iterationCell.indexOf(".")).trim();
if ((scriptCell.equals(scriptName) && iterationCell.equals(String.valueOf(iteration).trim()))
|| (scriptCell.equals(scriptName) && Integer.parseInt(iterationCell) == iteration))
rowNum = row.getRowNum();
found = true;
break;
if (rowNum == -1 || found == false)
throw new Exception("Please check the test name: " + scriptName + " or the iteration: " + iteration
+ " in the test data sheet");
row = sheet.getRow(0);
catch (Exception e)
e.printStackTrace();
public void getExcelColNum(String colName)
boolean found = false;
try
for (int i = 0; i < row.getLastCellNum(); i++)
if (row.getCell(i).getStringCellValue().trim().equals(colName.trim()))
col_Num = i;
found = true;
break;
if (col_Num == -1 || found == false)
throw new Exception("Please check the column name: " + colName + " in the test data sheet");
catch (Exception e)
e.printStackTrace();
public void getCell()
try
row = sheet.getRow(rowNum);
cell = row.getCell(col_Num);
catch (Exception e)
e.printStackTrace();
//Prior to calling this method. I am connecting to the excel sheet which
is in .xlsx or xls format
public String getEntireCellValue(String sheetName, String colName)
try
sheet = workbook.getSheet(sheetName);
getExcelRowNum();
getExcelColNum(colName);
getCell();
if (cell.getCellTypeEnum() == CellType.STRING)
return cell.getStringCellValue().trim();
else if (cell.getCellTypeEnum() == CellType.BLANK)
return null;
catch (Exception e)
e.printStackTrace();
return null;
public int getNumOfMergedRows()
int rowsMerged = 0;
try
for(int i = 0; i < sheet.getNumMergedRegions(); i++)
CellRangeAddress range = sheet.getMergedRegion(i);
if (range.getFirstRow() <= rowNum && range.getLastRow() >=
rowNum)
++rowsMerged;
System.out.println("Number of rows merged are: " + rowsMerged);
catch (Exception e)
e.printStackTrace();
return rowsMerged;
附:我在这里做的是,我正在尝试获取脚本的合并行数,例如为登录脚本合并 6 行,然后在这 6 行中查找单元格数以获得参考集名称(3 个单元格)。 注意:当我调用上述方法 - getNumOfMergedRows() 来确定为登录脚本合并的行数时,我得到 4 作为输出而不是 6。
【问题讨论】:
if 条件下 rowNum 变量的值是多少? 添加了我用来确定 rowNum 的代码。注意:所有变量都是实例变量 【参考方案1】:我有一个将字段作为输入的示例代码。它将计算第三列中所有值的值并将其存储在地图中。它通过计算 excel 文件中的空白值并在每个有效值处重置计数器来做到这一点
import java.io.File;
import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.IOException;
import java.util.HashMap;
import java.util.Iterator;
import java.util.Map;
import org.apache.poi.ss.usermodel.Cell;
import org.apache.poi.ss.usermodel.CellType;
import org.apache.poi.ss.usermodel.Row;
import org.apache.poi.ss.usermodel.Sheet;
import org.apache.poi.ss.usermodel.Workbook;
import org.apache.poi.xssf.usermodel.XSSFWorkbook;
public class Demo
public static void main(String[] args)
readFile(new File("excelstack.xlsx"));
public static void readFile(File file)
try
FileInputStream excelFile = new FileInputStream(file);
Workbook workbook = new XSSFWorkbook(excelFile);
Sheet datatypeSheet = workbook.getSheetAt(0);
Iterator<Row> iterator = datatypeSheet.iterator();
Map<String,Integer> map=new HashMap<String,Integer>();
int coltocheck=1;
int counter=1;
String currentitem="";
while (iterator.hasNext())
Row currentRow = iterator.next();
Iterator<Cell> cellIterator = currentRow.iterator();
while (cellIterator.hasNext())
Cell currentCell = cellIterator.next();
if(currentCell.getCellTypeEnum()==CellType.BLANK )
if(currentCell.getColumnIndex()==coltocheck)
map.put(currentitem, counter++);
else if(currentCell.getCellTypeEnum()==CellType.STRING && currentCell.getColumnIndex()==coltocheck)
currentitem=currentCell.getStringCellValue();
counter=1;
map.put(currentitem, counter++);
for(Map.Entry<String, Integer> m:map.entrySet())
System.out.println(m.getKey()+" "+m.getValue());
catch (FileNotFoundException e)
e.printStackTrace();
catch (IOException e)
e.printStackTrace();
finally
【讨论】:
【参考方案2】:以下代码将确定列中合并单元格的数量 - colName,开始行为startingRow
public int getNumOfMergedRows(String colName, int startingRow)
int rowsMerged = 0, col = 0;
XSSFRow mergedRow = null;
XSSFCell mergedCell = null;
try
col = getExcelColNum(colName);
for (int i = startingRow + 1; i < sheet.getPhysicalNumberOfRows(); i++)
mergedRow = sheet.getRow(i);
mergedCell = mergedRow.getCell(col);
if (mergedCell.getCellTypeEnum() == null || mergedCell.getCellTypeEnum() == CellType.BLANK)
rowsMerged++;
else
break;
rowsMerged++;
catch (Exception e)
e.printStackTrace();
logger.info(rowsMerged + " rows are merged in columne" + colName + " for " + scriptName + " script");
return rowsMerged;
【讨论】:
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