如何使用 spring rest 调用 URL？

Posted 2023-02-26

【中文标题】如何使用 spring rest 调用 URL？

【英文标题】：How to call a URL using spring rest?

【发布时间】：2018-02-01 19:20:51

【问题描述】：

我正在使用 spring rest 示例代码。我想从我的代码中调用一个 URL。我是新来的休息和春天。这是我的控制器

 @RestController
public class EmployeeRESTController 

    @RequestMapping(value = "/employees")
    public @ResponseBody EmployeeListVO getAllEmployees() 
    
        EmployeeListVO employees = new EmployeeListVO();

        EmployeeVO empOne = new EmployeeVO(1,"Lokesh","Gupta","[e-mail]");
        EmployeeVO empTwo = new EmployeeVO(2,"Amit","Singhal","[e-mail]");
        EmployeeVO empThree = new EmployeeVO(3,"Kirti","Mishra","[e-mail]");


        employees.getEmployees().add(empOne);
        employees.getEmployees().add(empTwo);
        employees.getEmployees().add(empThree);

        return employees;
    

    @RequestMapping(value = "/employees/id")
    @ResponseBody
    public ResponseEntity<EmployeeVO> getEmployeeById (@PathVariable("id") int id) 
    
        if (id <= 3) 
            EmployeeVO employee = new EmployeeVO(1,"Lokesh","Gupta","[e-mail]");
            return new ResponseEntity<EmployeeVO>(employee, HttpStatus.OK);
        
        return new ResponseEntity(HttpStatus.NOT_FOUND);
    

有模型类

    @XmlRootElement (name="employees")
public class EmployeeListVO

    private List<EmployeeVO> employees = new ArrayList<EmployeeVO>();

    public List<EmployeeVO> getEmployees() 
        return employees;
    

    public void setEmployees(List<EmployeeVO> employees) 
        this.employees = employees;
    


    @XmlRootElement (name = "employee")
@XmlAccessorType(XmlAccessType.NONE)
public class EmployeeVO implements Serializable

    private static final long serialVersionUID = 1L;

    @XmlAttribute
    private Integer id;

    @XmlElement
    private String firstName;

    @XmlElement
    private String lastName;

    @XmlElement
    private String email;

    public EmployeeVO(Integer id, String firstName, String lastName, String email) 
        super();
        this.id = id;
        this.firstName = firstName;
        this.lastName = lastName;
        this.email = email;
    

    public EmployeeVO()

    

    public Integer getId() 
        return id;
    

    public void setId(Integer id) 
        this.id = id;
    

    public String getFirstName() 
        return firstName;
    

    public void setFirstName(String firstName) 
        this.firstName = firstName;
    

    public String getLastName() 
        return lastName;
    

    public void setLastName(String lastName) 
        this.lastName = lastName;
    

    public String getEmail() 
        return email;
    

    public void setEmail(String email) 
        this.email = email;
    

    @Override
    public String toString() 
        return "EmployeeVO [id=" + id + ", firstName=" + firstName
                + ", lastName=" + lastName + ", email=" + email + "]";
    

当我调用 url localhost:8080/springrestexample/employees/ 时，会出现一些数据。现在我想修改这段代码。如果我调用上面的 url，我想将页面重定向到另一个 URL，例如 https://cp.lk/index.php/cbs/sms/send?

【问题讨论】：

您可以通过返回 http 302 请求浏览器执行此操作。

@ZakiAnwarHamdani 你能解释一下吗？

而不是 return new ResponseEntity(HttpStatus.NOT_FOUND);，尝试 return "redirect:cp.lk/index.php/cbs/sms/send";

@ZakiAnwarHamdani 返回 url 时我必须使用的方法的数据类型是什么

是HttpStatus = OK还是NOT_FOUND时重定向到URL？如果是OK，您还需要返回EmployeeVO 以及URL，因此需要相应地加载您的Response。

【参考方案1】：

@RestController
public class URLController 

  @RequestMapping("/foo")
  void urlFoo(HttpServletResponse response) throws IOException 
    response.sendRedirect("some-url");
  

【讨论】：

请解释为什么该代码可以解决问题中提出的问题。

【参考方案2】：

这里有很多解决方案：Redirect to an external URL from controller action in Spring MVC

例如使用 RedirectView

在您的用例中：

@RequestMapping(value = "/employees")
public RedirectView redirect() 

    return new RedirectView("https://cp.lk/index.php/cbs/sms/send");