由于语法错误表未在 DB 中创建
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【中文标题】由于语法错误表未在 DB 中创建【英文标题】:Due to syntax error table is not being created in DB 【发布时间】:2017-01-11 06:33:55 【问题描述】:// USER_REGISTRATION_DB(POJO class)
@Entity
@Table(name="USER_REGISTRATION_DB")
public class UserRegistration_DB
// this is for primary key
@Id
@GeneratedValue(strategy = GenerationType.TABLE)
@Column(name="USER-NO")
private int userno;
@Size(min=5, max = 5 ,message="please Enter char followed by NUM")
@NotNull
@Column(name="UUID")
private String uuid;
@Size(min = 2, max = 30,message="Please Enter More than One Character")
@Column(name = "FIRST_NAME")
private String first_name;
@Column(name = "LAST_NAME")
private String last_name;
@NotNull(message="Please Enter Correct DOB")
@DateTimeFormat(pattern="dd/mm/yyyy")
@Past
@Column(name = "DATE_OF_BIRTH")
private Date date_of_birth;
//@NotNull(message="Please Enter your Customer_Id")
@Column(name="AGE")
private String age;
//@NotEmpty(message="Please Enter your Email")
@Size(min = 12, max = 40,message="Please Enter More than Eleven Characters")
@Email(message="Please Enter Valid Email ID")
@Column(name = "EMAIL", unique=true)
private String email;
//@NotNull(message="Please Enter your Password")
@Size(min = 6, max = 30,message="Please Enter more than 6 Characters")
@Column(name = "PASSWORD")
private String password;
@NotNull(message="Please Enter mobile number")
@Column(name = "MOBILE")
private String mobile;
//@NotEmpty(message="Please Enter your Username")
@Size(min = 3, max = 40,message="Please Enter More than 2 Characters")
@Column(name="USERNAME")
private String username;
//@NotNull(message="Please Enter your streetName")
@Size(min = 2, max = 60,message="Please Enter More than 1 Characters")
@Column(name="ADDRESS")
private String address;
//@NotNull(message="Please Enter your Customer_Id")
@Column(name="V_ID")
private String vid;
// this my DAO class implementation
public void saveNewUser(
UserRegistration_DB userRegistration_DB)throws IOException
System.out.println("In User registration DB DAO class::::::::::"+userRegistration_DB.getFirst_name()+" "+userRegistration_DB.getUuid());
Session session = getSession(); //creating session
session.beginTransaction(); //begin transaction for the session.
Query query = session.createQuery("UPDATE UserRegistration_DB set first_name =:firstname,last_name =:lastname,username =:username,date_of_birth =:dob,Email =:email,password =:password,Mobile =:mobile,Address =:address,Age =:age" +
" Uuid =:uuid ");
query.setParameter("firstname",userRegistration_DB.getFirst_name());
query.setParameter("lastname",userRegistration_DB.getLast_name());
query.setParameter("mobile",userRegistration_DB.getMobile());
query.setParameter("email",userRegistration_DB.getEmail());
query.setParameter("dob",userRegistration_DB.getDate_of_birth());
query.setParameter("age",userRegistration_DB.getAge());
query.setParameter("password",userRegistration_DB.getPassword());
query.setParameter("username",userRegistration_DB.getUsername());
query.setParameter("uuid",userRegistration_DB.getUuid());
query.setParameter("address",userRegistration_DB.getAddress());
query.setParameter("vid",userRegistration_DB.getVid());
int user = query.executeUpdate();
session.save(userRegistration_DB);
System.out.println("user values are ::::::::::::::::::"+user);
session.getTransaction().commit(); //here transaction complete with commit the data in db.
session.close();
//session close
// this is controller class
//UserRegistrationController.java
@RequestMapping(value="/signup",method=RequestMethod.POST)
public String saveRegAction(@ModelAttribute("signup") @Validated UserRegistration_DB userRegistration_DB,BindingResult bindingResult,Model model,HttpSession session,HttpServletResponse servletResponse) throws Exception
System.out.println("the object is:" + model);
if(bindingResult.hasErrors())
logger.info("user details==========="+userRegistration_DB.getFirst_name()+""+userRegistration_DB.getLast_name()+""+userRegistration_DB.getMobile()+""+userRegistration_DB.getEmail()+""+
userRegistration_DB.getDate_of_birth()+""+userRegistration_DB.getAge()+""+userRegistration_DB.getPassword()+""+userRegistration_DB.getUsername()+""+userRegistration_DB.getAddress());
logger.info("Returning home.jsp page");
model.addAttribute("login", new Login());
model.addAttribute("user", new UserRegistration_DB());
return "signup";
//registerService.saveRegister(register);
userRegistrationService.saveNewUser(userRegistration_DB);
session.setAttribute("userRegistration_DB", userRegistration_DB);
return "main";
// error am getting is
// am Using mysql DB
// User_REGISTRATION_DB is not being created
/* HHH000388: 不成功: 创建表 USER_REGISTRATION_DB (USER-NO integer not null, ADDRESS varchar(60), AGE varchar(255), DATE_OF_BIRTH datetime not null, EMAIL varchar(40), FIRST_NAME varchar(30), LAST_NAME varchar(255), MOBILE varchar(255) not null, PASSWORD varchar(30), USERNAME varchar(40), UUID varchar(5) not null, V_ID varchar(255), 主键 (USER-NO))
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '-NO integer not null, ADDRESS varchar(60), AGE varchar(255), DATE_OF_BIRTH datet' at line 1 */
【问题讨论】:
问题与jsp无关。 【参考方案1】:在列名中使用连字符似乎是 Hibernate 的一个已知问题。
在 JPA 1.0 中,解决方法是使用反引号转义列名:
// this is for primary key
@Id
@GeneratedValue(strategy = GenerationType.TABLE)
@Column(name = "`USER-NO`")
private int userno;
在 JPA 2.0 及更高版本中,您可以简单地将列名放在引号中,例如
@Column(name = "\"USER-NO\"")
参考:
Creating field with reserved word name with JPA
【讨论】:
一般规则:尽可能避免使用此类名称以上是关于由于语法错误表未在 DB 中创建的主要内容,如果未能解决你的问题,请参考以下文章