从表中获取最后 200 条记录 [关闭]

Posted 2023-02-24

【中文标题】从表中获取最后 200 条记录 [关闭]

【英文标题】：Fetching last 200 records from table [closed]

【发布时间】：2015-08-13 05:49:03

【问题描述】：

我在数据库中有 1000 多条记录。我需要一个查询来仅选择最后 200 条记录。

SELECT 
      c.member_id, c.message_id, fm.firstname AS fname, up.gender,  
      TIMESTAMPDIFF( YEAR, up.dob, NOW( ) ) AS age, c.upload_img, c.image, 
      c.message_id AS msg_id, c.message AS msg, c.posted_timestamp AS time, 
      c.topic_id AS topic_id, u.croppedpicture_filename,u.picture_filename FROM 
      conversation_messages_tbl c, user_profileinformation_tbl up, user_tbl u, family_member_tbl fm 
WHERE c.member_id = fm.family_member_id AND
      up.user_id = fm.user_id AND 
      u.emailid = fm.emailid AND 
      c.topic_id = '1' 
      GROUP BY c.message_id desc LIMIT 200 sub ORDER BY c.message_id ASC

此查询无法执行。

【问题讨论】：

没问题。到目前为止，您尝试过什么？

你的代码在哪里？我们看不到任何努力。

我投票决定将此问题作为离题结束，因为没有显示任何解决问题的尝试。

Select last N rows from mysql的可能重复

【参考方案1】：

包含 order by 子句以获取最后 200 条记录。

SELECT c.member_id,c.message_id, fm.firstname AS fname, up.gender, 
TIMESTAMPDIFF( YEAR, up.dob, NOW( ) ) AS age, c.upload_img, c.image, 
c.message_id AS msg_id, c.message AS msg, c.posted_timestamp AS time, 
c.topic_id AS topic_id, u.croppedpicture_filename,u.picture_filename 
FROM conversation_messages_tbl c, user_profileinformation_tbl up, 
user_tbl u, family_member_tbl fm WHERE c.member_id = 
fm.family_member_id AND up.user_id = fm.user_id AND u.emailid = 
fm.emailid AND c.topic_id = '$topicId' GROUP BY c.message_id desc 
ORDER BY c.member_id DESC LIMIT 200