刷新页面后发布的文件[重复]
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【中文标题】刷新页面后发布的文件[重复]【英文标题】：Files being posted after refreshing page [duplicate] 【发布时间】：2017-03-16 05:51:44 【问题描述】：编辑：标记为重复，但是当我尝试时，帖子中的解决方案对我没有帮助。现在不想用ajax做，所以我只是用window.location来重定向。我丢失了上传文件的名称，但我宁愿以某种方式处理这些文件。
我有一个上传文件的表单，我发布到同一页面，提交后文件被上传，但如果我刷新文件会重新上传。我尝试在上传脚本的末尾将 $_POST 和 $_FILES 设置为空白数组，但每次仍然保留发布数据.. 还尝试添加标题，但它说它们已经发送，当我尝试在脚本开头使用 ob_start ，没有变化。
我的表格和表格是这样的
<table name="doctor_file_table" >
<tr>
<td><b>Name</b></td>
<td><b>Type</b></td>
<td><b>Size (bytes)</b></td>
<td><b>Created</b></td>
<td><a href='path_to_file' download =''>Download</a></td>
<td><button id ='id#' onClick='deleteFile(this)' type='button'>Delete</button></td>
</tr>
<form action="" enctype="multipart/form-data" method="post">
<div>
<label for="upload">Add Attachments:</label>
<input id="upload" name="upload[]" type="file" multiple="multiple"/>
</div>
<p><input type="submit" name="submit" value="Submit"></p>
</form>'
这里是上传脚本：
if(isset($_POST['submit']) && $_POST['uploaded'] == 1)
echo $_POST['uploaded'];
if(count($_FILES['upload']['name']) > 0)
//Loop through each file
for($i=0; $i<count($_FILES['upload']['name']); $i++)
//Get the temp file path
$tmpFilePath = $_FILES['upload']['tmp_name'][$i];
//Make sure we have a filepath
if($tmpFilePath != "")
//save the filename
$shortname = $_FILES['upload']['name'][$i];
//save the url and the file
$filePath = "/var/www/html/doctor_files/" . date('d-m-Y-H-i-s').'-'.$_FILES['upload']['name'][$i];
$fullname = substr($filePath,27);
//Upload the file into the temp dir
if(move_uploaded_file($tmpFilePath, $filePath))
$files[] = $shortname;
$sql = 'insert into '.TABLE_DOCTOR_FILES.'(shortname,fullname,filepath,type,size,doctor_id) VALUES("'.$shortname.'", "'.$fullname.'", "'.$filePath.'", "'.$_FILES["upload"]["type"][$i].'",'.$_FILES["upload"]["size"][$i].',"'.$doctor_id.'")';
database_void_query($sql);
//use $shortname for the filename
//use $filePath for the relative url to the file
//show success message
echo "<h1>Uploaded:</h1>";
if(is_array($files))
echo "<ul>";
foreach($files as $file)
echo "<li>$file</li>";
echo "</ul>";
【问题讨论】：
当你按f5时，页面即将再次发送POST请求。你应该使用ajax。阅读关于 ajax on MDN 是的，我认为有一种简单的方法可以清除数据，但我想还是这样更好。 【参考方案1】：请求标头将存储您的数据。因此，如果您刷新，数据将再次发送回来。
您有 3 个解决方案：
将您的代码分成 2 个不同的页面
使用ajax（当然这需要像no 1那样拆分页面）
尝试重定向到另一个页面，然后再次重定向到您的表单页面。
要使用第三种方式，你可以试试这个：
index.php
<html>
<head><title>asdas</title></head>
<body><!--i give you header to know this is will give error header or not-->
<?php
if(isset($_POST['submit']) && $_POST['uploaded'] == 1)
echo $_POST['uploaded'];
if(count($_FILES['upload']['name']) > 0)
//Loop through each file
for($i=0; $i<count($_FILES['upload']['name']); $i++)
//Get the temp file path
$tmpFilePath = $_FILES['upload']['tmp_name'][$i];
//Make sure we have a filepath
if($tmpFilePath != "")
//save the filename
$shortname = $_FILES['upload']['name'][$i];
//save the url and the file
$filePath = "/var/www/html/doctor_files/" . date('d-m-Y-H-i-s').'-'.$_FILES['upload']['name'][$i];
$fullname = substr($filePath,27);
//Upload the file into the temp dir
if(move_uploaded_file($tmpFilePath, $filePath))
$files[] = $shortname;
$sql = 'insert into '.TABLE_DOCTOR_FILES.'(shortname,fullname,filepath,type,size,doctor_id) VALUES("'.$shortname.'", "'.$fullname.'", "'.$filePath.'", "'.$_FILES["upload"]["type"][$i].'",'.$_FILES["upload"]["size"][$i].',"'.$doctor_id.'")';
database_void_query($sql);
//use $shortname for the filename
//use $filePath for the relative url to the file
//show success message
echo "<h1>Uploaded:</h1>";
header('Location: http://localhost/***/success.php');
if(is_array($files))
echo "<ul>";
foreach($files as $file)
echo "<li>$file</li>";
echo "</ul>";
?>
<table name="doctor_file_table" >
<tr>
<td><b>Name</b></td>
<td><b>Type</b></td>
<td><b>Size (bytes)</b></td>
<td><b>Created</b></td>
<td><a href='path_to_file' download =''>Download</a></td>
<td><button id ='id#' onClick='deleteFile(this)' type='button'>Delete</button></td>
</tr>
<form action="" enctype="multipart/form-data" method="post">
<div>
<label for="upload">Add Attachments:</label>
<input id="upload" name="upload[]" type="file" multiple="multiple"/>
</div>
<p><input type="submit" name="submit" value="Submit"></p>
</form>
成功.php
<html><head><title>redirect</title></head>
<body><!--i give you header to know this is will give error header or not-->
<?php
echo "<p>Your upload is success</p>";
echo "<p>You will redirect back</p>";
echo "<p><a href=\"index.php\">or press this to redirect directly</a></p>";
?>
<script>
setTimeout(function ()
window.location.href = "index.php";
, 3000);
</script>
</body></html>
【讨论】：
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