在 Swift 中推送 iOS8 的通知状态

Posted 2023-02-24

【中文标题】在 Swift 中推送 iOS8 的通知状态

【英文标题】：Push notification status for iOS8 in Swift

【发布时间】：2015-08-19 06:57:57

【问题描述】：

我一直在寻找关于在 ios8 的 Swift 中设置推送通知的适当教程，但我觉得从 Objective-C 到 Swift 以及从 iOS7 到 iOS8 已经进行了很多更改，尽管我找不到任何更新的部分的代码。

我想知道用户是否按下了推送通知警报中的“不允许”按钮和/或者他们是否曾经看到过。

事实是，在这种情况下，我希望显示一个警报，要求用户通过设置重新允许通知。

问题：我不知道要检查哪个变量才能知道是否应该显示弹出窗口。

我可以使用它，但哈希值在两种情况下都为 0，其中 1- 推送通知警报从未显示，2- 推送通知警报已显示但用户推送“不允许”。

if(UIApplication.sharedApplication().currentUserNotificationSettings().hashValue == 0)
            pushNotificationStatus = "false"
         else 
            pushNotificationStatus = "true"
        

您有解决此问题的最佳做法/想法吗？ 谢谢你！

【问题讨论】：

这可能会有所帮助：***.com/questions/25111644/…

【参考方案1】：

//Write belkow code in Appdelegate.m in didfinishLaunching mehod..

  Register for Push Notitications, if running iOS 8
if application.respondsToSelector("registerUserNotificationSettings:") 

  let types:UIUserNotificationType = (.Alert | .Badge | .Sound)
  let settings:UIUserNotificationSettings = UIUserNotificationSettings(forTypes: types, categories: nil)

  application.registerUserNotificationSettings(settings)
  application.registerForRemoteNotifications()

 else       
  // Register for Push Notifications before iOS 8
  application.registerForRemoteNotificationTypes(.Alert | .Badge | .Sound)

可以进入didFailToRegisterForRemoteNotificationsWithError

  func application(
        application: UIApplication,
        didRegisterForRemoteNotificationsWithDeviceToken deviceToken: NSData
    ) 


         //Process the deviceToken and send it to your server
         let trimEnds = 
          deviceToken.description.stringByTrimmingCharactersInSet(
          NSCharacterSet(charactersInString: "<>"))
            
         let cleanToken = 
          trimEnds.stringByReplacingOccurrencesOfString(
           " ", withString: "", options: nil)
           
        

    func application(
        application: UIApplication,
        didFailToRegisterForRemoteNotificationsWithError error: NSError
    ) 
        //Log an error for debugging purposes, user doesn't need to know
        NSLog("Failed to get token; error: %@", error) 
    

收到通知后，以下代表将调用：

func application(application: UIApplication, didReceiveRemoteNotification userInfo: [NSObject : AnyObject]) 

    println("Recived: \(userInfo)")
   //Parsing userinfo:
   var temp : NSDictionary = userInfo
   if let info = userInfo["aps"] as? Dictionary<String, AnyObject> 
            
                var alertMsg = info["alert"] as! String
                var alert: UIAlertView!
                alert = UIAlertView(title: "", message: alertMsg, delegate: nil, cancelButtonTitle: "OK")
                alert.show()
            

并且可以控制 UIApplication.sharedApplication().currentUserNotificationSettings() 的哈希值。

if(UIApplication.instancesRespondToSelector(Selector("registerUserNotificationSettings:")))
        if(UIApplication.sharedApplication().currentUserNotificationSettings().hashValue == 0)
            pushNotificationStatus = "false"
         else 
            pushNotificationStatus = "true"
        

【讨论】：

我看不出它是如何回答我的问题的。我如何知道警报是否已经显示？谢谢

【参考方案2】：

iOS 10.0 起可以使用此方法

UNUserNotificationCenter.current().getNotificationSettings(completionHandler:   settings in
     switch settings.authorizationStatus 
     case .notDetermined:
         print("Not determined")
     case .denied: //In this case user has already seen this alert, and answered "Don't allow"
         print("Denied") 
     case .authorized:
         print("Authorised")