尝试从远程通知中快速从 didReceive 响应中运行函数

Posted 2023-02-24

【中文标题】尝试从远程通知中快速从 didReceive 响应中运行函数

【英文标题】：Attempting to run a function from inside the didReceive response in swift from a remote notification

【发布时间】：2021-06-24 18:56:16

【问题描述】：

所以我有一个设置，我正在尝试学习如何使用 firebase 和 swift 制作一个基本的聊天应用程序。我已经设置了所有通知类别，我可以获取通知，并且可以单击我设置的操作。我开始升级它以允许在通知操作中“回复”，这就是我遇到问题的地方。

在 didReceive 响应的 userNotificationCenter 方法中，我需要能够调用 ApiService 以将消息发送到我的节点服务器，该服务器通过管理 sdk 直接与 firebase 通信。问题是，每次我尝试从该函数内部调用一个方法时，都会出现错误：

没有更多上下文的表达类型是模棱两可的

这是我的didReceive 方法，为了简单起见，在这篇文章中进行了简化...

func userNotificaitonCenter(_ center: UNUsernotificationCenter, didReceive response: UNNotificationResponse, withCompletionHandler completionHandler: @escaping () -> Void) 
  let userInfor = response.notificaiton.request.content.userInfo
  switch response.actionIdentifier 
    case Notifications.Actions.reply:
      let textResponse = response as! UNTextInputNotificationResponse
      let userText = textResponse.userText
      let messageFrom = userInfo["from"]
      let myID = userInfo["to"]
      ApiService.sendNewMessage(myId, to: messageFrom, message: userText)  (_) in  <-This line gives the error
      break
    ...
 

我尝试通过在 AppDelegate 类中添加私有方法然后调用该方法来更改它，但我仍然遇到相同的错误。我不明白为什么它认为表达式是模棱两可的，我的项目中除了我构建的那个之外没有其他 ApiService 类。 我这样做完全错了吗？我只是希望能够将用户在通知中键入的消息发送回服务器，以便可以将其添加到聊天中。提前感谢您的任何帮助，这个让我挠头，掉头发。

【问题讨论】：

尝试将每个参数的类型强制为预期类型。

您的函数类型不同，我认为它是字符串或 int 并且 userInfo["to"] 返回任何类型，因此您需要转换值

【参考方案1】：

这里有很多错别字 - 有些是允许的，有些会造成您所面临的问题。

/// 1. `userNotificaitonCenter` - typo in Notification - allowed (you may be able to compile with it, SDK won't be able provide you this callback
/// 2. `center: UNUsernotificationCenter` - small n in notification (invalid type name - not allowed to compile - which you are seeing the compiler complaining about in it's weirdest form)
/// 3. `response.notificaiton.request.content.userInfo` - typo in `notification` (not allowed to compile)
/// 4. `let userInfor = ...` vs `userInfo["from"]` - compiler has no idea what `userInfo` is - it only knows about `userInfor` 
/// 5. `let userInfor = ...` vs `userInfo["to"]` - compiler has no idea what `userInfo` is - it only knows about `userInfor` 
/// 6. `ApiService.sendNewMessage` - Is it a class/static method or instance method? Do you want to do something like ApiService.shared.sendNewMessage ???
/// 7. `ApiService.sendNewMessage(myId, to: messageFrom` Does it expect String in both of these parameters? OR Int in first & String in second parameter?
func userNotificaitonCenter(_ center: UNUsernotificationCenter, didReceive response: UNNotificationResponse, withCompletionHandler completionHandler: @escaping () -> Void) 
  let userInfor = response.notificaiton.request.content.userInfo
  switch response.actionIdentifier 
    case Notifications.Actions.reply:
      let textResponse = response as! UNTextInputNotificationResponse
      let userText = textResponse.userText
      let messageFrom = userInfo["from"]
      let myID = userInfo["to"]
      ApiService.sendNewMessage(myId, to: messageFrom, message: userText)  (_) in  <-This line gives the error
      break
    ...
 

更新

它应该是这样的（错别字已修复，添加了一些虚拟 ApiService 代码以使其编译）

import Foundation
import UserNotifications

class ApiService 
    static let shared = ApiService()
    func sendNewMessage(to toID: Int, from fromID: Int, message: String) 


class Test: NSObject, UNUserNotificationCenterDelegate 
    func userNotificationCenter(_ center: UNUserNotificationCenter, didReceive response: UNNotificationResponse, withCompletionHandler completionHandler: @escaping () -> Void) 
        let userInfo = response.notification.request.content.userInfo
        switch response.actionIdentifier 
        case "reply":
            let textResponse = response as! UNTextInputNotificationResponse
            let userText = textResponse.userText
            let from = userInfo["from"] as? Int ?? 0
            let to = userInfo["to"] as? Int ?? 0
            ApiService.shared.sendNewMessage(to: to, from: from, message: userText)
            break
        default: break