XMPP:如何解析 XMPPMessage 元素
Posted
技术标签:
【中文标题】XMPP:如何解析 XMPPMessage 元素【英文标题】:XMPP: How to parse XMPPMessage element 【发布时间】:2017-01-10 11:03:14 【问题描述】:我为来自 xmpp 的每条消息获取以下 xml 格式
- (void)xmppStream:(XMPPStream *)sender didReceiveMessage:(XMPPMessage *)message
NSLog(@"Message %@",message);
在控制台打印
<message
xmlns="jabber:client" from="10000006956@xmpp-dev.peeks.com" to="10000006956@xmpp-dev.peeks.com/mobile">
<result
xmlns="urn:xmpp:mam:tmp" id="1483781596098940">
<forwarded
xmlns="urn:xmpp:forward:0">
<message
xmlns="jabber:client" from="10000006931@xmpp-dev.peeks.com/mobile" to="10000006956@xmpp-dev.peeks.com" type="chat">
<body>Hi</body>
<delay
xmlns="urn:xmpp:delay" from="xmpp-dev.peeks.com" stamp="2016-12-22T04:50:17.023Z">Offline Storage
</delay>
</message>
<delay
xmlns="urn:xmpp:delay" from="xmpp-dev.peeks.com" stamp="2017-01-07T09:33:16.099Z">
</delay>
</forwarded>
</result>
</message>
我想从每条消息中获取“from”、“to”、“body”和“stamp”,我做了以下操作
NSXMLElement *body = message;
NSXMLElement *messageb = [body elementForName:@"result" xmlns:@"urn:xmpp:mam:tmp"];
NSXMLElement *forwa=[messageb elementForName:@"forwarded" xmlns:@"urn:xmpp:forward:0"];
NSXMLElement *msg=[forwa elementForName:@"message" xmlns:@"jabber:client"];
NSXMLElement *TD=[forwa elementForName:@"delay" xmlns:@"urn:xmpp:delay"];
NSString *from=[[msg elementForName:@"from" xmlns:@"jabber:client"] stringValue];
NSString *to=[[msg elementForName:@"to" xmlns:@"jabber:client"] stringValue];
NSString *bodyq=[[msg elementForName:@"body"] stringValue];
NSString *stmp=[[TD elementForName:@"stamp" xmlns:@"urn:xmpp:delay"] stringValue];
NSString *final=[NSString stringWithFormat:@"From: %@\nTo: %@\nBody: %@\nStamp: %@",from,to,bodyq,stmp];
NSLog(@"forwa %@", final);
我只能打印消息正文和日志打印像
From: (null)
To: (null)
Body: hi
Stamp: (null)
【问题讨论】:
【参考方案1】:修复搜索属性:元素是节点(如 Body、Result 等),而其他只是先前元素的属性。
NSString *from=[[msg attributeForName:@"from"] stringValue];
NSString *to=[[msg attributeForName:@"to"] stringValue];
NSString *stmp=[[TD attributeForName:@"stamp"] stringValue];
已编辑(抱歉,我最后一次使用 ObjectiveC 的工作太旧了)。
xml namespace
是关于 element
而不是 attributes
。
如果没有再次获取,请尝试通过 NSXMLNode 传递
NSXMLNode *fromNode = [msg attributeForName:@"from"];
NSString *from = [fromNode stringValue];
【讨论】:
它给出的错误 No Visible @interface for 'DDXMLElement' 声明了选择器 'attributeForName:xmlns:' 刚刚从每一行中删除了 xmlns:@"jabber:client" 然后它的工作正常更新你的答案oooo 你能告诉我如何从下面的 xml 中获取这些值对于 Swift 5:
func xmppStream(_ sender: XMPPStream, didReceive message: XMPPMessage)
if let msg = message.body
if let from = message.attribute(forName: "from")?.stringValue
print("msg: \(msg), \(from)")
【讨论】:
以上是关于XMPP:如何解析 XMPPMessage 元素的主要内容,如果未能解决你的问题,请参考以下文章
如何在 Swift 语言中使用 XMPPStream XMPP 框架发送图像?
Swift 3 XMPP框架在XMPPMessageArchiving_Message_CoreDataObject中正确使用了willInsert()和didUpdate()