快速从 Url 获取 Imagename

Posted 2023-02-23

【中文标题】快速从 Url 获取 Imagename

【英文标题】：Get Imagename from Url in swift

【发布时间】：2016-07-08 16:15:14

【问题描述】：

我有这个网址https://storage.googleapis.com/user_avatars/63/img_-qLgH80SBqNhMRYbDQeccg.jpg 我只需要来自此链接的 qLgH80SBqNhMRYbDQeccg 图像名称 In ui Image

【参考方案1】：

您可以使用 NSURL 安全地隔离文件名，然后使用子字符串来获取您想要的部分。

let s = "https://storage.googleapis.com/user_avatars/63/img_-qLgH80SBqNhMRYbDQeccg.jpg"

斯威夫特 2

if let url = NSURL(string: s),
    withoutExt = url.URLByDeletingPathExtension,
    name = withoutExt.lastPathComponent 
    let result = name.substringFromIndex(name.startIndex.advancedBy(5))
    print(result)

斯威夫特 3

if let url = URL(string: s),
    withoutExt = try? url.deletingPathExtension(),
    name = withoutExt.lastPathComponent 
    let result = name.substring(from: name.index(name.startIndex, offsetBy: 5))
    print(result)

斯威夫特 4

if let url = URL(string: s) 
    let withoutExt = url.deletingPathExtension()
    let name = withoutExt.lastPathComponent
    let result = name.substring(from: name.index(name.startIndex, offsetBy: 5))
    print(result)

---

打印：

qLgH80SBqNhMRYbDQeccg

【参考方案2】：

使用NSURLComponents 分解 URL 的东西怎么样：

func parseURLForFileName(url:String) ->String?

    let components = NSURLComponents(string: url)
    if let path:NSString = components?.path
    
        let filename = path.lastPathComponent
        if let range = filename.rangeOfString("_-")
        
            return filename.substringFromIndex(range.endIndex)
        
    
    return nil

然后你可以这样称呼它：

    let name = parseURLForFileName("https://storage.googleapis.com/user_avatars/63/img_-qLgH80SBqNhMRYbDQeccg.jpg")
    print(name)