Google Maps SDK iOS - 根据缩放级别计算半径

Posted 2023-02-23

【中文标题】Google Maps SDK iOS - 根据缩放级别计算半径

【英文标题】：Google Maps SDK iOS - Calculate radius according zoom Level

【发布时间】：2015-11-03 19:07:56

【问题描述】：

我需要根据相机缩放级别计算半径以在地图上显示标记。现在我有 SouthWestCorner 和我的位置是我的 MapView 的中心。当缩放改变时，我需要缩小并计算新的半径。

有人知道如何从我拥有的数据中获取它吗？

我的代码在这里：

func mapView(mapView: GMSMapView!, idleAtCameraPosition position: GMSCameraPosition!) 

        println("latitude: \(position.target.latitude) longtitude: \(position.target.longitude)")

        var visibleRegion = mapView.projection.visibleRegion()
        var cameraZoom = mapView.camera.zoom
        var bounds = GMSCoordinateBounds(region: visibleRegion)
        var southWestCorner = bounds.southWest

    

【参考方案1】：

您可以使用mapView.projection.visibleRegion() 查找可见屏幕上的角坐标。

func mapView(_ mapView: GMSMapView, idleAt position: GMSCameraPosition) 
    
    // Find the coordinates
    let visibleRegion = mapView.projection.visibleRegion()
    let farLeftLocation = CLLocation(latitude: visibleRegion.farLeft.latitude, longitude: visibleRegion.farLeft.longitude)
    let centerLocation = CLLocation(latitude: position.target.latitude, longitude: position.target.longitude)

    // Calculate the distance as radius.
    // The distance result from CLLocation is in meters, so we divide it by 1000 to get the value in kilometers
    let radiusKM = centerLocation.distance(from: farLeftLocation) / 1000.0

    // Do something with the radius...

【参考方案2】：

将 Antons anwser 更新为 Swift 3 并作为 GMSMapView 的扩展

extension GMSMapView 
    func getCenterCoordinate() -> CLLocationCoordinate2D 
        let centerPoint = self.center
        let centerCoordinate = self.projection.coordinate(for: centerPoint)
        return centerCoordinate
    

    func getTopCenterCoordinate() -> CLLocationCoordinate2D 
        // to get coordinate from CGPoint of your map
        let topCenterCoor = self.convert(CGPoint(x: self.frame.size.width, y: 0), from: self)
        let point = self.projection.coordinate(for: topCenterCoor)
        return point
    

    func getRadius() -> CLLocationDistance 
        let centerCoordinate = getCenterCoordinate()
        let centerLocation = CLLocation(latitude: centerCoordinate.latitude, longitude: centerCoordinate.longitude)
        let topCenterCoordinate = self.getTopCenterCoordinate()
        let topCenterLocation = CLLocation(latitude: topCenterCoordinate.latitude, longitude: topCenterCoordinate.longitude)
        let radius = CLLocationDistance(centerLocation.distance(from: topCenterLocation))
        return round(radius)
    

调用self.map.getRadius() 将返回半径

【参考方案3】：

好的，我已经为我的问题找到了很好的答案。也许它对其他人有帮助。根据这个article

要获得半径应该使用下一个示例（所有函数都转换为 swift）：

// calculate radius
    func getCenterCoordinate() -> CLLocationCoordinate2D 
        var centerPoint = self.mapView.center
        var centerCoordinate = self.mapView.projection.coordinateForPoint(centerPoint)
        return centerCoordinate
    

    func getTopCenterCoordinate() -> CLLocationCoordinate2D 
        // to get coordinate from CGPoint of your map
        var topCenterCoor = self.mapView.convertPoint(CGPointMake(self.mapView.frame.size.width / 2.0, 0), fromView: self.mapView)
        var point = self.mapView.projection.coordinateForPoint(topCenterCoor)
        return point
    

    func getRadius() -> CLLocationDistance 

        var centerCoordinate = getCenterCoordinate()
        // init center location from center coordinate
        var centerLocation = CLLocation(latitude: centerCoordinate.latitude, longitude: centerCoordinate.longitude)
        var topCenterCoordinate = self.getTopCenterCoordinate()
        var topCenterLocation = CLLocation(latitude: topCenterCoordinate.latitude, longitude: topCenterCoordinate.longitude)

        var radius = CLLocationDistance(centerLocation.distanceFromLocation(topCenterLocation))

        return round(radius)
    

【参考方案4】：

您应该使用near/far+Left/Right，而不是southWest。请参阅GMSVisibleRegion Struct Reference。原因是西南不包括 3D 地图的情况。

得到farRight、farLeft、nearRight、nearLeft后，可以计算出两条水平边的两个中点之间的距离，以及垂直边的距离。然后你选择较小的值，这应该是你的半径。

【讨论】：

谢谢，有例子或公式吗？

我认为谷歌地图有计算两点之间距离的功能。此外，由于 lat/lng 是度数，而中点只是 [ (FL.lat+NL.lat)/2, (FL.lng + NL.lng)/2 ] 和 [ (FR.lat+NR.lat)/2, (FR.lng + NR.lng)/2 ]。