按下设备后退按钮上的 Flutter WebView 异常

Posted 2023-02-23

【中文标题】按下设备后退按钮上的 Flutter WebView 异常

【英文标题】：Flutter WebView exception on device back button pressed

【发布时间】：2020-08-03 10:13:11

【问题描述】：

我对 Flutter 很陌生，所以如果这是一个基本问题，请原谅我。

我正在尝试创建一个仅显示全屏 web 视图的 Flutter 应用程序，但我需要设备返回按钮才能返回历史记录。第一项任务我很轻松地完成了，但第二项任务却是一场斗争。

我按照answer 中的说明进行操作，但我无法消除仅按后退按钮的 360 多行答案的所有混乱并使其正常工作。

我的代码很简单：

import 'dart:io';
import 'package:flutter/material.dart';
import 'package:flutter/services.dart';
import 'package:webview_flutter/webview_flutter.dart';

void main() => runApp(MyApp());

WebViewController _controller;

Future<void> _onWillPop(BuildContext context) async 
  if (await _controller.canGoBack()) 
    _controller.goBack();
   else 
    exit(0);
    return Future.value(false);
  


class MyApp extends StatelessWidget 
  @override
  Widget build(BuildContext context) 
    SystemChrome.setEnabledSystemUIOverlays([]);
    return WillPopScope(
      onWillPop: () => _onWillPop(context),
      child: MaterialApp(title: 'Test App', home: WebView(
      initialUrl: 'https://google.com',
      javascriptMode: JavascriptMode.unrestricted,
      onWebViewCreated: (WebViewController c) => _controller = c,
    )),
    );
  

但是当我尝试按下设备返回按钮时，它会抛出以下错误：

java.lang.RuntimeException: Cannot execute operation because FlutterJNI is not attached to native.
    at io.flutter.embedding.engine.FlutterJNI.ensureAttachedToNative(FlutterJNI.java:227)
    at io.flutter.embedding.engine.FlutterJNI.markTextureFrameAvailable(FlutterJNI.java:554)
    at io.flutter.embedding.engine.renderer.FlutterRenderer.markTextureFrameAvailable(FlutterRenderer.java:274)
    at io.flutter.embedding.engine.renderer.FlutterRenderer.access$300(FlutterRenderer.java:38)
    at io.flutter.embedding.engine.renderer.FlutterRenderer$SurfaceTextureRegistryEntry$1.onFrameAvailable(FlutterRenderer.java:145)
    at android.graphics.SurfaceTexture$1.handleMessage(SurfaceTexture.java:211)
    at android.os.Handler.dispatchMessage(Handler.java:107)
    at android.os.Looper.loop(Looper.java:224)
    at android.app.ActivityThread.main(ActivityThread.java:7520)
    at java.lang.reflect.Method.invoke(Native Method)
    at com.android.internal.os.RuntimeInit$MethodAndArgsCaller.run(RuntimeInit.java:539)
    at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:950)

flutter 的 github 上至少有 3 个线程，但没有一个解决方案对我有用。我在这里错过了什么？

【问题讨论】：

我认为这是因为您没有使用 Completer

是的，但我似乎也需要一个有状态的小部件。

【参考方案1】：

您可以在下面复制粘贴运行完整代码 您可以使用Completer 代码 sn -p

WebViewController controller;

final Completer<WebViewController> _controllerCompleter =
          Completer<WebViewController>();
...
onWebViewCreated: (WebViewController c) 
                _controllerCompleter.future.then((value) => controller = value);
                _controllerCompleter.complete(c);
              ,

工作演示

完整代码

import 'dart:io';
import 'package:flutter/material.dart';
import 'package:flutter/services.dart';
import 'package:webview_flutter/webview_flutter.dart';
import 'dart:async';

void main() 
  runApp(MyApp());


class MyApp extends StatelessWidget 
  @override
  Widget build(BuildContext context) 
    return MaterialApp(
      title: 'Flutter Demo',
      theme: ThemeData(
        primarySwatch: Colors.blue,
        visualDensity: VisualDensity.adaptivePlatformDensity,
      ),
      home: MyHomePage(title: 'Flutter Demo Home Page'),
    );
  


class MyHomePage extends StatefulWidget 
  MyHomePage(Key key, this.title) : super(key: key);

  final String title;

  @override
  _MyHomePageState createState() => _MyHomePageState();


class _MyHomePageState extends State<MyHomePage> 
  WebViewController controller;

  final Completer<WebViewController> _controllerCompleter =
      Completer<WebViewController>();

  Future<void> _onWillPop(BuildContext context) async 
    print("onwillpop");
    if (await controller.canGoBack()) 
      controller.goBack();
     else 
      exit(0);
      return Future.value(false);
    
  

  @override
  Widget build(BuildContext context) 
    return WillPopScope(
      onWillPop: () => _onWillPop(context),
      child: Scaffold(
        body: WebView(
          initialUrl: 'https://flutter.dev/',
          javascriptMode: JavascriptMode.unrestricted,
          onWebViewCreated: (WebViewController c) 
            _controllerCompleter.future.then((value) => controller = value);
            _controllerCompleter.complete(c);
          ,
        ),
      ),
    );
  

【讨论】：

很高兴为您提供帮助。如果对您有帮助，请将其标记为答案。谢谢。

【参考方案2】：

在 Android MainActivity.kt 中，只需添加以下内容：

override fun onDestroy()  flutterEngine?.platformViewsController?.onFlutterViewDestroyed() super.onDestroy() 

【参考方案3】：

这是可行的解决方案（100% 工作）-

  // Use any webview plugin
  // WebView _controller;

  Future<void> _handleBack(context) async 
    var status = await _controller.canGoBack();
    if (status) 
      _controller.goBack();
     else 
      showDialog(
          context: context,
          builder: (context) => AlertDialog(
                title: Text('Do you want to exit'),
                actions: <Widget>[
                  FlatButton(
                    onPressed: () 
                      Navigator.of(context).pop();
                    ,
                    child: Text('No'),
                  ),
                  FlatButton(
                    onPressed: () 
                      SystemNavigator.pop();
                    ,
                    child: Text('Yes'),
                  ),
                ],
              ));
    
  

这里是调用 WillPopScope

  @override
  Widget build(BuildContext context) 
    return WillPopScope(
            onWillPop: () => _handleBack(context),
            child: SafeArea(
              top: true,
              child: Scaffold(......)))