java.lang.IllegalArgumentException:服务未注册 Flutter 和 Firebase Google SignIn
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【中文标题】java.lang.IllegalArgumentException:服务未注册 Flutter 和 Firebase Google SignIn【英文标题】:java.lang.IllegalArgumentException: Service not registered Flutter and Firebase Google SignIn 【发布时间】:2021-03-26 02:38:18 【问题描述】:我想允许使用 Firebase 在我的应用中通过 google 登录。这是我的代码:
import 'package:PixiCall/models/user.dart';
import 'package:PixiCall/utils/utilities.dart';
import 'package:cloud_firestore/cloud_firestore.dart';
import 'package:firebase_auth/firebase_auth.dart';
import 'package:google_sign_in/google_sign_in.dart';
class FirebaseMethods
final FirebaseAuth _auth = FirebaseAuth.instance;
GoogleSignIn _googleSignIn = GoogleSignIn();
static final FirebaseFirestore firestore = FirebaseFirestore.instance;
//user class
User1 user = User1();
Future<User> getCurrentUser() async
User currentUser;
currentUser = await _auth.currentUser;
return currentUser;
Future<User> signIn() async
GoogleSignInAccount _signInAccount = await _googleSignIn.signIn();
GoogleSignInAuthentication _signInAuthentication =
await _signInAccount.authentication;
final AuthCredential credential = GoogleAuthProvider.credential(
accessToken: _signInAuthentication.accessToken,
idToken: _signInAuthentication.idToken,
);
User user = (await _auth.signInWithCredential(credential)).user;
return user;
Future<bool> authenicateUser(User user) async
QuerySnapshot result = await firestore
.collection('users')
.where('email', isEqualTo: user.email)
.get();
final List<DocumentSnapshot> docs = result.docs;
//if user is registered then length of list > 0 or else less than 0
return docs.length == 0 ? true : false;
Future<void> addDataToDb(User currentUser) async
String username = Utils.getUsername(currentUser.email);
user = User1(
uid: currentUser.uid,
email: currentUser.email,
name: currentUser.displayName,
profilePhoto: currentUser.photoURL,
username: username);
firestore.collection('users').doc(currentUser.uid).set(user.toMap(user));
而且 VS Code 中没有错误,我在运行应用程序时在终端中出现此消息:
/ConnectionTracker(14606): Exception thrown while unbinding
W/ConnectionTracker(14606): java.lang.IllegalArgumentException: Service not registered: lv@b068d66
W/ConnectionTracker(14606): at android.app.LoadedApk.forgetServiceDispatcher(LoadedApk.java:1484)
W/ConnectionTracker(14606): at android.app.ContextImpl.unbindService(ContextImpl.java:1638)
W/ConnectionTracker(14606): at android.content.ContextWrapper.unbindService(ContextWrapper.java:703)
W/ConnectionTracker(14606): at ci.f(:com.google.android.gms.dynamite_measurementdynamite@204516052@20.45.16 (040700-0):1)
W/ConnectionTracker(14606): at ci.d(:com.google.android.gms.dynamite_measurementdynamite@204516052@20.45.16 (040700-0):2)
W/ConnectionTracker(14606): at lw.E(:com.google.android.gms.dynamite_measurementdynamite@204516052@20.45.16 (040700-0):9)
W/ConnectionTracker(14606): at lg.a(:com.google.android.gms.dynamite_measurementdynamite@204516052@20.45.16 (040700-0):3)
W/ConnectionTracker(14606): at eg.run(:com.google.android.gms.dynamite_measurementdynamite@204516052@20.45.16 (040700-0):3)
W/ConnectionTracker(14606): at java.util.concurrent.Executors$RunnableAdapter.call(Executors.java:457)
W/ConnectionTracker(14606): at java.util.concurrent.FutureTask.run(FutureTask.java:266)
W/ConnectionTracker(14606): at iz.run(:com.google.android.gms.dynamite_measurementdynamite@204516052@20.45.16 (040700-0):5)
这是登录按钮:
Widget loginButton()
return FlatButton(
padding: EdgeInsets.all(35),
child: Text(
'Login',
style: TextStyle(
fontSize: 25,
fontWeight: FontWeight.w900,
letterSpacing: 1.2,
),
),
onPressed: () => performLogin,
);
void performLogin()
_repository.signIn().then((User user)
if (user != null)
authenticateUser(user);
else
print('There was an error');
);
另外,在 VS Code 的问题选项卡中,我有这个错误:“等待”应用于“用户”,这不是“未来”。此错误与我提供的第一个代码有关。
当我点击登录按钮时,什么也没有发生。它应该让我使用 Google 登录,但它没有。有人知道这可能是什么问题吗?
【问题讨论】:
您是否为 Firebase 提供了 SHA1 密钥?为了能够在 android 上使用 google 登录,您需要提供密钥 是的,我在 Firebase 控制台中提供了它。 :) 【参考方案1】:您不需要使用async
方法来调用getCurrentUser()
。
User getCurrentUser()
User currentUser;
currentUser = _auth.currentUser;
return currentUser;
【讨论】:
我试过你的代码,在此之后,我将 firebase_repository.dart 文件从:Future以上是关于java.lang.IllegalArgumentException:服务未注册 Flutter 和 Firebase Google SignIn的主要内容,如果未能解决你的问题,请参考以下文章