为最终用户处理 Flutter 上的 Firebase 身份验证错误

Posted 2023-02-23

【中文标题】为最终用户处理 Flutter 上的 Firebase 身份验证错误

【英文标题】：Handle Firebase Auth Errores on Flutter for End Users

【发布时间】：2021-08-18 07:58:27

【问题描述】：

每次我得到一个错误，例如在登录屏幕上：“无效密码”，我都会得到一个带有如下消息的字符串：

如何将此消息更改为用户友好的消息？我尝试使用在另一篇文章中找到的以下代码：

class Errors 
  static String show(String errMsg) 
    switch (errMsg) 
      case 'ERROR_EMAIL_ALREADY_IN_USE':
        return "This e-mail address is already in use, please use a different e-mail address.";

      case 'ERROR_INVALID_EMAIL':
        return "The email address is badly formatted.";

      case 'ERROR_ACCOUNT_EXISTS_WITH_DIFFERENT_CREDENTIAL':
        return "The e-mail address in your Facebook account has been registered in the system before. Please login by trying other methods with this e-mail address.";

      case 'ERROR_WRONG_PASSWORD':
        return "E-mail address or password is incorrect.";

      default:
        return "An error has occurred";
    
  

但它总是在屏幕上显示默认错误。我尝试在这些案例上使用“firebase_auth/wrong-password”或“wrong-password”，但没有奏效。有没有人有更好的解决方案？我是新手！

【问题讨论】：

***.com/questions/56113778/… 我想这正是你要找的东西

我去看看试试看！

【参考方案1】：

尝试在此处阅读此文档：

https://firebase.flutter.dev/docs/auth/usage

正如您在文档中看到的那样，字母是小写字母，并由“-”分隔。

【参考方案2】：

I searched a bit on the post from ZOthix and i did find the solution.

I post it here for anyone who needs it:

class Errors 
  static String show(String errMsg) 
    switch (errMsg) 
      case "email-already-in-use":
        return "Email already used. Go to login page.";
        break;
      case "wrong-password":
        return "Wrong email/password combination.";
        break;
      case "user-not-found":
        return "No user found with this email.";
        break;
      case "user-disabled":
        return "User disabled.";
        break;
      case "ERROR_TOO_MANY_REQUESTS":
      case "operation-not-allowed":
        return "Too many requests to log into this account.";
        break;
      case "ERROR_OPERATION_NOT_ALLOWED":
      case "operation-not-allowed":
        return "Server error, please try again later.";
        break;
      case "invalid-email":
        return "Email address is invalid.";
        break;
      default:
        return "Login failed. Please try again.";
        break;